Hoval DGV-6/30, Руководство по конструкции

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5.2 Horizontal air flow
Design data Example
■ Geometry of the room
■ Fabric heat losses
■ Room temperature
■ Extract air temperature
(Because of the low height, room temperature = extract air temperature is used in this example.)
■ Distance from ceiling
Geometry ..................................15 × 20 × 3 m
Fabric heat losses .....................38 kW
Room temperature ....................20 °C
Extract air temperature..............20 °C
Distance from ceiling .................0.6 m
Mounting height
■ Calculate the actual mounting height (= distance between the floor and the bottom edge of
the units).
H = Hall height – distance from ceiling – unit height
■
Compare the actual mounting height with the minimum and maximum mounting height
(see Table D10).
GV-3/30
→
OK
GV-5/50
→
OK
Minimum number of units
■ Determine the minimum number of units for each unit type. Take into account the following criteria:
– Heat output
– Unit clearances and reach
Type
Required number
Minimum number
of units
Heat output
Unit clearances
and reach
GV-3/30 2 2 2
GV-5/50 1 2 2
■ Choose the final solution from the remaining possibilities, depending on the geometry of the hall and the costs.
When positioning the units consider the following:
■ Do not direct the air current directly at persons.
■ Do not install the units at too great a distance from the
ceiling, in order to avoid the formation of warm air pockets.
■ The units can also be arranged opposite each other or
opposite and offset.
Fig. D3: Offset arrangement of the units on opposing walls
D
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TopVent ® GV
Design example Design example