- 7 -
k
K
k
K
l
L
l
L
Feed 1
Feed 2
K L K L
Measurement via sum current converter
P.F.Controller
Current
measurement
k l
k l
Example:
C.converter 1: 1000/5A
C.converter 2: 1000/5A
Sum-current converter: 5A+5A / 5A
C.converter ratio is: 2000 /5A
Connection of current transformer / sum current transformer
When installing the current converter, care should be taken to ensure that the load
current flows through it. The outputs of the compensation network must be installed
behind the current converter (in the direction of current flow). If the
is connected
up via sum-current converters, the overall conversion ratio is entered.
Caution!
The secondary clamps of the CT
have to be short circuited before
current leads are iterrupted !
BR7000
!
BR7000 in High Voltage Application
The example shows the connection of BR7000 in HV-application.
The measuring current is taken off primary via X/1A transformer. Measuring voltage
produced via transformer 20000/100 V. In this case, the BR7000 has to be programmed
as follows:
4 I-CONVERTER sek: X / 1A
14 MEASUR.VOLTAGE (L-N): 100 V: 1,73 = 58V
15 V-CONVERTER:
20kV / 100 V
L1 (R)
L1 (R)
L2 (S)
L2 (S)
L3 (T)
L3 (T)
N
Meas.current
Im (X/1A)
supply
voltage
Ub
Meas-
voltage
Um
BR 7000
PE
Meas.current
Meas. voltage Um
Supply voltage Ub
L1 L2 L3
L1 L2 L3 N
L1 N
HIGH VOLTAGE LOW VOLTAGE
20 kV / 400 V
20000
100
