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SECTION IV
3-1-2010
Page 4-5
Design
STEP NO. 6 – DETERMINE TOTAL ATOMIZER PRES-
SURE (TAP)
6a – Size Piping and Calculate Pipe Pressure Loss
(PPL) in Supply Line A
Linear Length A1 through A4 + equivalent lengths of all
fittings in each pipe line x pressure loss (see Table 2) =
Pipe Pressure Loss (PPL).
Example:
3/4 in. Schedule 40 piping:
Length A1, 16.17 ft (4.929 m) + A2, 6 ft (1.829 m) + A3,
12 ft (3.658 m) + A4, 4 ft (1.219 m) = 38.17 ft (11.634 m)
Equivalent length of 3/4 in. elbow = 2 ft (0.610 m) (see
Table 1)
Three elbows in Supply Line A = 3 x 2 ft (0.610 m) (equiv-
alent length per elbow) = 6 ft (1.829 m)
38.17 ft (11.634 m) + 6 ft (1.829 m) = 44.17 ft (13.463 m)
total equivalent length of pipe
Select the correct pressure from Table 2 for the number of
atomizers flowing through this pipe section. Since there
are four atomizers, the pressure loss factor would be
0.10027 psi/ft (0.02267 bar/m) (see Table 2).
Pressure loss for Supply line A = 44.17 ft (13.463 m) of
3/4 in. pipe x 0.10027 psi/ft (0.02267 bar/m) = 4.43 psi
(0.305 bar).
6b – Size Piping and Calculate Pipe Pressure Loss
(PPL) in Branch Line B
Linear length B1 and B2 + equivalent lengths of all fittings
in each pipe line x pressure loss (see Table 2) = Pipe
Pressure Loss (PPL).
Example:
1/2 in. Schedule 40 piping:
Length B1, 9.25 ft (2.819 m) + B2, 6.59 ft (2.009 m) =
15.84 ft (4.828 m)
Equivalent length of 1/2 in. elbow = 1 ft (0.30m) (see
Table 1)
One elbow in Branch Line B = 1 x 1 ft (0.30m) (equivalent
length per elbow) = 1 ft (0.30m)
Equivalent length of 1/2 in. tee = 3 ft (0.91 m) (see Table
1)
One tee in Branch Line B = 1 x 3 ft (0.91 m) (equivalent
length per side tee) = 3 ft (0.91 m)
15.84 ft (4.828 m)+ 1 ft (0.30m) + 3 ft (0.91 m) = 19.84 ft
(6.047 m) total equivalent feet of pipe
Select the correct pressure from Table 2 for the number of
atomizers flowing through this pipe section. Since there
are two atomizers, the pressure loss factor would be
0.10912 psi/ft (0.02467 bar/m) (see Table 2).
Pressure loss for Branch Line B = 19.84 ft (6.047 m) of
1/2 in. pipe x 0.10912 psi/ft (0.02467 bar/m) = 2.16 psi
(0.149 bar)
6c – Size Piping and Calculate Pipe Pressure Loss
(PPL) in Branch Line C
Linear length C1 + equivalent lengths of all fittings in each
pipe line x pressure loss (see Table 2) = Pipe Pressure
Loss (PPL).
Example:
1/2 in. Schedule 40 piping:
Length C1, 2.92 ft (0.89 m) =2.92 ft (0.89 m)
Equivalent length of 1/2 in. side tee = 3 ft (0.91 m) (see
Table 1)
One (1) tee in Branch Line F = 1 x 3 ft (0.91 m) (equiva-
lent length per elbow) = 3 ft (0.91 m)
2.92 ft (0.89 m) + 3 ft (0.91 m) = 5.92 ft (1.80 m) total
equivalent feet of pipe.
Select the correct pressure from Table 2 for the number of
atomizers flowing through this pipe section. Since there is
one atomizer, the pressure loss factor would be 0.03023
psi/ft (0.00683 bar/m) (see Table 2).
Pressure loss for Branch Line C = 5.92 ft (1.80 m) of 1/2
in. pipe x 0.03023 psi/ft (0.00683 bar/m) = 0.18 psi (0.012
bar)
Summary of Contents for ANSUL AQUASONIC
Page 84: ...SECTION V 3 1 2010 Page 5 14 NOTES Installation ...
Page 88: ...SECTION VII 3 1 2010 Page 7 2 Inspection NOTES ...
Page 94: ...SECTION VIII 3 1 2010 Page 8 6 NOTES Maintenance ...
Page 116: ...APPENDIX C 3 1 2010 Page C 2 Main and Reserve Systems NOTES ...
Page 134: ...APPENDIX D 3 1 2010 Page D 18 008567 Typical Examples ...
Page 135: ...APPENDIX D 3 1 2010 Page D 19 008568 Typical Examples ...
Page 136: ...APPENDIX D 3 1 2010 Page D 20 008569 Typical Examples ...
Page 137: ...APPENDIX D 3 1 2010 Page D 21 008570 Typical Examples ...
Page 138: ...APPENDIX D 3 1 2010 Page D 22 008571 Typical Examples ...
Page 139: ...APPENDIX D 3 1 2010 Page D 23 008572 Typical Examples ...
Page 140: ...APPENDIX D 3 1 2010 Page D 24 008573 Typical Examples ...
Page 141: ...APPENDIX D 3 1 2010 Page D 25 008574 Typical Examples ...