25
EN
W415-1398 / C / 06.15.17
Example:
V
1
= 2 FT (0.6m)
V
2
= 1 FT (0.3m)
V
3
= 1.5 FT (0.5m)
T
1
2
3
H
1
= 6 FT (1.8m)
H
2
= 2 FT (0.6m)
H
R
=
H
1
+ H
2
= 6FT (1.8m) + 2FT (0.6m) = 8 FT (2.4m)
Formula 1:
H
T
< 3.5 V
T
T
Since this formula is not met, this vent configuration is
unacceptable.
Formula 2:
T
T
H
1
= 1 FT (0.3m)
H
2
= 1 FT (0.3m)
H
3
= 10.75 FT (3.3m)
H
R
= H
1
+ H
2
+ H
3
= 1FT (0.3m) + 1FT (0.3m) + 10.75FT (3.3m) = 12.75FT (3.9m)
H
O
= .03 (three 90° one 45° elbow - 90°)
= .03 (270° + 45° - 90°) = 6.75 FT (2.1m)
H
T
= H
R
+ H
O
= 12.75FT (3.9m) + 6.75FT (2.1m) = 19.5
FT (5.9m) H
T
+ V
T
= 19.5FT (5.9m) + 6.5FT (2m) = 26 FT (7.9m)
Formula 1:
H
T
< 3 V
T
3 V
T
= 3FT (0.9m) x 6.5FT (2m) = 19.5FT (5.9m)
Fig. 1
Summary of Contents for CB30NTR
Page 11: ...11 EN W415 1398 C 06 15 17 3 2 TYPICAL VENT INSTALLATION...
Page 12: ...12 EN W415 1398 C 06 15 17 See VENTING section...
Page 42: ...42 EN W415 1398 C 06 15 17 5 1 MINIMUM FRAMING DIMENSIONS...
Page 46: ...46 EN W415 1398 C 06 15 17 MAXIMUM REAR VENT CLEARANCES EXAMPLE 1...
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