V
V
V
V
V
ts
t FwdZ
VT s
VT p
=
×
×
=
×
×
=
1 1
1 1 11931
0 1
13 8
95 1
.
.
.
.
.
,
,
,
EQUATION14057 V1 EN-US
(Equation 23)
∠
=
=
=
V
ForwardX
ForwardR
ts
arctan
arctan
.
.
59 33
8 19
82..14
°
EQUATION14058 V1 EN-US
(Equation 24)
frequency of V
ts
= 50 Hz
I
I
I
I
A
s
CTs
CTp
50
50
10459
1
9000
1 162
=
×
=
×
=
.
EQUATION14059 V1 EN-US
(Equation 25)
∠
I
50s
= 0º
frequency of
I
50s
= 50 Hz
It
I
I
I
A
fs
CTs
CTp
tf
=
×
=
×
=
10459
1
9000
1 162
.
EQUATION14062 V1 EN-US
(Equation 26)
∠
I
tfs
= 180º
frequency of
I
tfs
= 49.5 Hz
Expected result: the protection function does not issue either start or trip.
The trajectory of the impedance traverses the lens characteristic in zone 2
GUID-9F0FE404-6D83-4308-9FE4-13259CE7D07A v1
Preliminary steady state test at 50 Hz
GUID-700F4EA1-B7D9-4B77-829A-433BB67C8A01 v1
•
Go to Main menu/Test/Function status/Impedance protection/OutOfStep(78,Ucos)/
OOSPPAM(78,Ucos):1/Outputs to check the available service values of the function block
OOSPPAM.
•
Apply the following three-phase symmetrical quantities (the phase angle is related to
phase L1):
V
V
V
V
V
ts
t FwdZ
VT s
VT p
=
×
×
=
×
×
=
0 9
0 9 11931
0 1
13 8
77 81
.
.
.
.
.
,
,
,
EQUATION14063 V1 EN-US
(Equation 27)
∠
=
=
=
V
ForwardX
ForwardR
ts
arctan
arctan
.
.
59 33
8 19
82..14
°
EQUATION14058 V1 EN-US
(Equation 28)
frequency of V
ts
= 50 Hz
I
I
I
I
A
s
CTs
CTp
50
50
10459
1
9000
1 162
=
×
=
×
=
.
EQUATION14059 V1 EN-US
(Equation 29)
∠
I
50s
= 0º
frequency of
I
50s
= 50 Hz
It
I
I
I
A
fs
CTs
CTp
tf
=
×
=
×
=
10459
1
9000
1 162
.
EQUATION14062 V1 EN-US
(Equation 30)
∠
I
tfs
= 0º
1MRK 502 067-UEN B
Section 12
Testing functionality by secondary injection
137
Commissioning manual