Note that these values identify a point inside the lens characteristic, in the Zone 2, that is close
to the boundary between zone 1 and zone 2. The START is issued, but no TRIP is performed.
Execution of the dynamic test
GUID-53964189-42E4-4C4B-BFCD-64888BA938EF v1
The test may be performed by using two states of a sequence tool that is a basic feature of
test sets.
•
State 1: pre-test condition.
Steady voltage and current are applied in order to get a steady high impedance, that is a
point in the plane R-X that is far away from the lens characteristic. Define the following
three-phase symmetrical quantities (the phase angle is related to phase L1):
V
V
V
V
V
ts
t RZ
VT s
VT p
=
×
×
=
×
×
=
1 1
1 1 1435
0 1
13 8
11 44
1
.
.
.
.
.
,
,
,
EQUATION14065 V1 EN-US
(Equation 41)
∠
=
=
=
V
ForwardX
ForwardR
ts
arctan
arctan
.
.
59 33
8 19
82..14
°
EQUATION14058 V1 EN-US
(Equation 42)
frequency of V
t
= 50 Hz.
I
50s
= 0 A
I
tfs
= 0 A
•
State 2: main test step.
Define the following three-phase symmetrical quantities (the phase angle is related to
phase L1):
V
V
V
V
V
ts
t RZ
VT s
VT p
=
×
×
=
×
×
=
1 1
1 1 1435
0 1
13 8
11 44
1
.
.
.
.
.
,
,
,
EQUATION14065 V1 EN-US
(Equation 43)
∠
=
=
=
V
ForwardX
ForwardR
ts
arctan
arctan
.
.
59 33
8 19
82..14
°
EQUATION14058 V1 EN-US
(Equation 44)
frequency of V
t
= 50 Hz
I
I
I
I
A
s
CTs
CTp
50
50
10459
1
9000
1 162
=
×
=
×
=
.
EQUATION14059 V1 EN-US
(Equation 45)
∠I
50s
= 0º
frequency of I
50s
= 50 Hz
It
I
I
I
A
fs
CTs
CTp
tf
=
×
=
×
=
10459
1
9000
1 162
.
EQUATION14062 V1 EN-US
(Equation 46)
∠I
tfs
= 180º
frequency of I
tfs
= 49.5 Hz
Expected result: start of the protection function and trip in zone 2 when trip conditions
are fulfilled.
Section 12
1MRK 502 067-UEN B
Testing functionality by secondary injection
140
Commissioning manual
