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B-13
Appendix B
Appendix B
P50 or
P
O
2
(0.5)*
The
P
50 is defined as the
P
O
2
of a sample at which the
hemoglobin is 50% saturated with oxygen at pH 7.4, 37°C,
and 40 mm Hg
P
CO
2
for
S
O
2
% values between 40% and
80%.
P
50
(uncorrected)
=
P
O
2
/(
S
O
2
%/(100-
S
O
2
%))
0.37
Equation 30
For measured
S
O
2
% between 80 and 96.9%, the equation
is as follows:
Where z = tanh(0.5343
*
x); x = ln(0.133
*
P
O
2
/7); y =
ln(
S
O
2
%/(100-
S
O
2
%))-1.875
P
50
(uncorrected)
=26.902
*
exp(1.121
*
(y-x-3.5z)/(1.87
*
z
2
+
z - 2.87)) Equation 31
The corrected equation is as follows:
log P50
(corrected)
= log P50
(uncorrected)
+ 0.43 (pH – 7.4) –
0.05 (log
P
CO
2
/40) – 0.0131(T – 37)
Equation 32
* The equations are from Reference 4.
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