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We find two critical points, one at x = 11/3 and one at x = -1. To evaluate the
second derivative at each point use:
The last screen shows that f”(11/3) = 14, thus, x = 11/3 is a relative minimum.
For x = -1, we have the following:
This result indicates that f”(-1) = -14, thus, x = -1 is a relative maximum.
Evaluate the function at those points to verify that indeed f(-1) > f(11/3).
Higher order derivatives
Higher order derivatives can be calculated by applying a derivative function
several times, e.g.,
Содержание 50G
Страница 1: ...HP g graphing calculator user s guide H Edition 1 HP part number F2229AA 90006 ...
Страница 130: ...Page 2 70 The CMDS CoMmanDS menu activated within the Equation Writer i e O L CMDS ...
Страница 177: ...Page 4 10 Function DROITE is found in the command catalog N Using EVAL ANS 1 simplifies the result to ...
Страница 206: ...Page 5 29 LIN LNCOLLECT POWEREXPAND SIMPLIFY ...
Страница 257: ...Page 7 20 ...
Страница 383: ...Page 11 56 Function KER Function MKISOM ...
Страница 715: ...Page 21 68 Whereas using RPL there is no problem when loading this program in algebraic mode ...
Страница 858: ...Page L 5 ...