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an expression = 0. Thus, the last set of equations is interpreted to be the
following equivalent set of equations:
X +2Y+3Z = 7,
Y+ Z = 3,
-7Z = -14.
The process of backward substitution in Gaussian elimination consists in finding
the values of the unknowns, starting from the last equation and working
upwards. Thus, we solve for Z first:
Next, we substitute Z=2 into equation 2 (E2), and solve E2 for Y:
Next, we substitute Z=2 and Y = 1 into E1, and solve E1 for X:
The solution is, therefore, X = -1, Y = 1, Z = 2.
Example of Gaussian elimination using matrices
The system of equations used in the example above can be written as a matrix
equation
A
⋅
x
=
b
, if we use:
Содержание 50G
Страница 1: ...HP g graphing calculator user s guide H Edition 1 HP part number F2229AA 90006 ...
Страница 130: ...Page 2 70 The CMDS CoMmanDS menu activated within the Equation Writer i e O L CMDS ...
Страница 177: ...Page 4 10 Function DROITE is found in the command catalog N Using EVAL ANS 1 simplifies the result to ...
Страница 206: ...Page 5 29 LIN LNCOLLECT POWEREXPAND SIMPLIFY ...
Страница 257: ...Page 7 20 ...
Страница 383: ...Page 11 56 Function KER Function MKISOM ...
Страница 715: ...Page 21 68 Whereas using RPL there is no problem when loading this program in algebraic mode ...
Страница 858: ...Page L 5 ...