Harmonic Drive LynxDrive Series, Руководство пользователя

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40
1018856 08/2018 V04
Load rotation speed n
2
= 40 [rpm]
Load torque (e. g. friction) T
L
= 5 [Nm]
Load inertia J
L
= 1.3 [kgm
2
]
Speed pattern
Acceleration; Deceleration t
1
= t
3
= 0.1 [s]
Operate with rated speed t
2
= 0.1 [s]
Stand still t
p
= 1 [s]
Total cycle time t
O
= 1.3 [s]
Load Conditions
Assume servo mechanism is used to cyclically position a mass with a horizontal axis of rotation.
Speed patt
ern
Torque patt
ern
n
2
= 40 rpm
Speed n [rpm]
T
1
T
2
T
3
t
1
= 0.1
t
2
= 0.1 t
3
= 0.1 t
P
= 1
Torque T [Nm]
t
0
= 1.3
Note t
1
= t
3
Time t [s]
Time t [s]
Please note:
Each characteristic value should be converted to the value at the output shaft of the actuator.
Max. Torque T
max
= 127 [Nm]
Max. Speed n
max
= 112 [rpm]
Moment of inertia J
Out
= 1.063 [kgm 2 ]
Actuator data CanisDrive-25A-50
Example of actuator selection
Table 40.1
Illustration 40.2
Table 40.3