PP610/612 LED lighting controllers - User Manual
calculate the maximum continuous current that the lights can take apply
the following formula:
I
MAX
=
I
R
÷
V
R
Where:
I
MAX
= Maximum continuous current in Amps
I
R
= Rated wattage in Watts
V
R
= Rated voltage in Volts
8.3
Power supply
The PP610 has split power input connectors for the control circuit and the
two output channels. This is so that crosstalk between the outputs can be
minimised when one channel has a high output current.
Start by wiring up the PP610 as described in
. It is possible to run the two channels and digital system from
two or three separate supplies as shown in
, though this will rarely be necessary.
Power supplies should be regulated with SELV compliant outputs (fault
tolerant). Consideration should be given to fusing VS1+ and VS2+. The
fuse value can be based on the average current output.
Note:
In Europe fuses are designed to pass at their rated current, while in
the USA fuses are designed to blow at their rated current.
8.3.1
Single supply applications
The diagram overleaf shows the normal supply wiring scheme for the
PP610. The three ground connections and VS connections are
commoned.
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