© EA Elektro-Automatik in 2022, this information is subject to change without notice
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06230820_manual_psi_10000_3u_15kw_en_01
3.10.5
Sine wave function
The following parameters can be configured for a sine wave function:
Parameter
Range
Description
Frequency (f)
1...10000 Hz
Static frequency of the signal to be generated
Amplitude (A)
0...(Nominal value - O) of U, I
Amplitude of the signal to be generated
Offset (O)
A...(Nominal value - A) of U, I
Offset, based on the zero point of the mathematical sine curve, may
not be smaller than the amplitude.
Schematic diagram:
Application and result:
Offset
Am
plitud
e
t
U,I
f
Am
plitud
e
A normal sine wave signal is generated and applied to the selected
set value, e.g. voltage (U). At a constant load resistance, the output
voltage and thus also the output current will follow a sine wave.
For calculating the maximum power output the amplitude and offset
values for the current have to be added.
Example: an output voltage of 100 V is set together with sin(I) with
an amplitude of 30 A and an offset of 50 A. The resulting maximum
power output is then achieved at the highest point of the sine wave
and is (30 A + 50 A) * 100 V = 8000 W.
It means, the global power limit would have to be set to at least 8000
W in order to achieve a function run as expected.
3.10.6
Triangular function
The following parameters can be configured for a triangular wave function:
Parameter
Range
Description
Amplitude (A)
0...(Nominal value - O) of U, I
Amplitude of the signal to be generated
Offset (O)
0...(Nominal value - A) of U, I
Offset, based on the foot of the triangular wave
Time t1
0.1 ms...36,000,000 ms
Rising edge time Δt of the triangular wave signal
Time t2
0.1 ms...36,000,000 ms
Falling edge time Δt of the triangular wave signal
Schematic diagram:
Application and result:
O
ffset
t
U,I
A
m
plit
ud
e
t1
t2
A triangular wave signal for output current (only effective in current
limiting) or output voltage is generated. The positive and negative
slope times can be set independently.
The offset shifts the signal on the Y-axis.
The sum of the intervals t1 and t2 gives the cycle time and its recip-
rocal is the frequency.
Example: a frequency of 10 Hz is required and would lead to periodic
duration of 100 ms. This 100 ms can be freely allocated to t1 and t2,
e.g. 50 ms:50 ms (isosceles triangle) or 99.9 ms:0.1 ms (right-angled
triangle or sawtooth).