Exhaust system
30
Example:
Engine:
D2MH
Power:
294 kW / 800 rpm
Silencer:
7" HD
Calculation of pressure loss through the silencer.
Bore velocity (m/s) =
Q (flow) = 2952 m
3
/h =
=
= 0.82 m
3
/s
– the value originates from
Technical Data in Sales Guide Marine Propulsion Diesel Engines.
Pipe area =
m
2
D = 7" = 0.75 m
Pipe area will be
A = 0.0240 m
2
Bore velocity = 34. m/s
From the diagram on previous page, one will find the resistance in mm Wc.
The resistance is approx 99 mm Wc.
The pressure loss will be calculated according to the formula:
Pressure loss (mm Wc) =
=
= 8 mm Wc
T = Exhaust gas Temperature
T = 293 °C (See
Technical Data in Sales Guide Marine Propulsion Diesel Engines.)
Pressure loss will be:
P
loss
= 8 mm Wc = .57 kPa
The pressure loss through the silencer is .873 kPa
NOTE! Check that the total backpressure (silencer backpressure and piping backpressure) is within the limits in
table in chapter
Backpressure.
Q (m
3
/min)
Pipe area (m
2
) x 60
2952 m
3
/h
3600 s
Resistance from graph (mm Wc) x 673
T °C + 273
2952
3600
π
x D
2
4
99 x 673
293 + 273
Summary of Contents for D11 series
Page 1: ...Marine Propulsion Diesel Engines Installation 1 1 D E D5 D16 series ...
Page 2: ......
Page 208: ...206 References to Service Bulletins Group No Date Concerns ...
Page 209: ...207 Notes ...
Page 210: ...208 Notes ...
Page 212: ...7748655 English 11 2007 ...