Page 16 of 51
6.6 Example of a Flue Resistance Calculation
Boilers:
4 x 150 kW + 1 x 180 kW; Total 780 kW
Horizontal air inlet:
5 meter
Vertical air inlet to the roof:
8 meter
T-pieces over the boilers
4
Number of bends 90°:
2
Roof
terminal:
1
Air inlet: Choosing a diameter of: 180 mm
Resistance
Horizontal duct , 5 meter
5 x 5.8
29.0 Pa
Vertical duct, 8 meter
8 x 5.8
46.4 Pa
Bends 90°:x 2
2 x 5.8
11.6 Pa
T-pieces:
x.4
4
x
5.8
23.2
Pa
Roof terminal
5.8
5.8 Pa
Total
116 Pa
Flue gas exhaust Choosing a diameter of: 180 mm
Resistance
Horizontal flue , 5 meter
5 x 8.4
42.0 Pa
Vertical flue, 8 meter
8 x 8.4
67.2 Pa
Bends 90°: x 2
2 x 8.4
16.8 Pa
T-pieces:
x.4
4
x
8.4
33.6
Pa
Roof terminal
8.4
8.4 Pa
Total
168.0 Pa
Total resistance of the system : 116 Pa+168Pa = 284 Pa
Total resistance is 284 Pa; higher than 250 Pa,(at which the Boiler output stays the same as stated on the
data plate) therefore according to the table on page
12
, the output will be lowered by about 3%.
This means, that the total output will be 780 kW – 3% = 756 kW
6.7 Chosing a diameter of 150 mm for the whole 780 kW system,
Air inlet system
: (uses flue material)
Choosing a diameter of: 150 mm
Resistance
Horizontal duct, 5 meter
5 x 15
75 Pa
Vertical duct, 8 meter
8 x 15
120 Pa
Bends 90°: x. 2
2 x 15
30 Pa
T-pieces: x. 4
4 x 15
60 Pa
Roof terminal
15
15 Pa
Total
300 Pa
Flue
Choosing a diameter of: 150 mm
Resistance
Horizontal Flue, 5 meter
5 x 23
115 Pa
Vertical Flue, 8 meter
8 x 23
204 Pa
Bends 90°: x. 2
2 x 23
46 Pa
T-pieces:
x.
4
4
x
23
102
Pa
Roof terminal
23
23 Pa
Total
490 Pa
Total resistance: 300+490 = 790 Pa. It is clear, that the resistance is higher than the 250 Pa, even higher than
the
maximum 600 Pa
;
the diameter of 150 mm is too small
.