FastTrak SX4030, SX4060, S150 SX4-M User Manual
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How can I change the resources that the FastTrak uses?
The FastTrak SX4030, SX4060 and S150 SX4-M are fully PnP. This means
all the resources that it uses are given to it by the PnP BIOS on the
motherboard.
The FastTrak Controller supports IRQ sharing, but this feature only works
when ALL the concerned devices support it. If your motherboard allows you
to control the assignment of these resources, you may be able to remedy the
problem by:
•
Changing the IRQ assignments to the PCI slots in the motherboard
BIOS during boot up.
•
Reset the configuration data in your CMOS. This is usually an option in
the PnP section of your CMOS.
•
Otherwise, switch the FastTrak Controller card to a different PCI slot.
How do the FastTrak SX4030, SX4060 and S150 SX4-M RAID Controllers
provide storage and data protection with their arrays?
FastTrak SX4030, SX4060 and S150 SX4-M implement five RAID levels as
follows:
RAID 0 (Stripe)
For capacity – The FastTrak RAID 0 array will be as big as the smallest HDD
in the array times however many HDDs are in the array. Any larger HDDs
will simply be truncated. The truncated space on the bigger HDDs will then
be unusable.
For sustained data transfers – Using a FastTrak Controller, a RAID 0 array
consisting of two HDDs will transfer at about twice the speed of the slowest
HDD in the array. A RAID 0 array consisting of four HDDs will transfer at
about three times the speed of the slowest HDD in the array.
RAID 1 (Mirror)
For capacity – The FastTrak RAID 1 array will be as big as the smallest HDD
in the array. The larger HDD will simply be truncated. The truncated space
on the bigger HDD will then be unusable.
For sustained data transfers – The FastTrak RAID 1 array will write data at
the rate of the slowest HDD in the array. The FastTrak array will read data at
twice the rate of the slowest HDD in the array.
RAID 0+1 (Stripe/Mirror)
For capacity – The FastTrak RAID 0+1 array will be one-half the size of the
smallest HDD in the array. The larger HDDs will be truncated. The truncated
space on the bigger HDDs will then be unusable.
