3 - 13
S.D. R2
MEE15K052
3. Piping Design
3-3. Refrigerant charging calculation
<Amount of refrigerant to be added>
The amount of refrigerant that is shown in the table below is factory-charged to the outdoor units.
The amount necessary for extended pipe (field piping) is not included and must be added on site.
Round up the calculation result to the nearest 0.1kg. (Example: 18.04kg to 18.1kg)
× 2
Outdoor unit model
Amount of pre-charged refrigerant
in the outdoor unit (kg)
Outdoor unit model Amount of pre-charged refrigerant
in the outdoor unit (kg)
P200YLM
9.5
P400YLM
10.3
P250YLM
9.5
P450YLM
11.8
P300YLM
10.3
P500YLM
11.8
P350YLM
10.3
Outdoor unit model Amount of pre-charged refrigerant
in the outdoor unit (kg)
EP200YLM
6.0
EP250YLM
6.0
EP300YLM
8.0
EP350YLM
8.0
EP400YLM
10.5
EP450YLM
11.8
EP500YLM
11.8
■ Calculation formula
The amount of refrigerant to be added depends on the size and the length of field piping. (unit in m[ft])
1) When the distance between HBC and outdoor unit is longer than 30.5m:
Amount of added refrigerant (kg) = (0.21xL
1
)+(0.14xL
2
)+(0.1xL
3
)+α
1
2) When the distance between HBC and outdoor unit is 30.5m or shorter:
Amount of added refrigerant (kg) = (0.23xL
1
)+(0.16xL
2
)+(0.11xL
3
)+α
1
L
1
: Length of ø22.20 [7/8"] high pressure pipe (m)
L
2
: Length of ø19.05 [3/4"] high pressure pipe (m)
L
3
: Length of ø15.88 [5/8"] high pressure pip (m)
α
1
: Refer to the table below.
Use of one HBC controller
Outdoor unit index
Diameter of high-pressure pipe
(E)P200
ø15.88
(E)P250
ø19.05
(E)P300
ø19.05
(E)P350
ø19.05
Amount for the HBC controller
α1 (kg)
α1 (kg)
3.0
Use of two HBC controllers
Outdoor unit index
Diameter of high-pressure pipe
(E)P300
ø19.05
(E)P350
ø19.05
(E)P400
ø22.20
(E)P450
ø22.20
Amount for the HBC controller
3.0
(E)P500
ø22.20
Example
■ Sample calculation
A
Outdoor unit
(~(E)P350)
HBC controller
Indoor unit
(15 ~ 50)
Indoor unit
(15 ~ 50)
Indoor unit
(15 ~ 50)
Indoor unit
(15 ~ 50)
A
B
C
D
Outdoor unit
((E)P300~)
HBC controller
HBC controller
Indoor unit
(15 ~ 50)
Indoor unit
(15 ~ 50)
Indoor unit
(15 ~ 50)
Indoor unit
(15 ~ 50)
Indoor
1: 50
A: ø19.05
42 m
2: 50
3: 50
4: 40
Outdoor
P250
The total length of each liquid line is as follows:
ø19.05: A = 42 m, α
1
= 3.0
Therefore,
<Calculation example>
Additional refrigerant charge
= 42 × 0.14 + 3.0
= 8.88 kg
* All pipe work except A is water pipe work.
Indoor
1: 50
A:ø22.20
18 m
2: 50
B:ø15.88
5 m
3:
50
C:ø15.88
10
m
4: 50
D:ø15.88
8 m
Outdoor P400
The total length of each liquid line is as follows:
ø22.20: A = 18 m, ø15.88: B + C + D = 23m, α
1
= 3.0 × 2
Therefore,
<Calculation example>
Additional refrigerant charge
= 18 × 0.23+ (5 + 10 + 8) × 0.11 + 3.0 × 2
= 12.67 kg
* All pipe work except A, B, C, D is water pipe work.
= 8.9 kg
= 12.7 kg
0000003906.BOOK 13 ページ 2016年2月18日 木曜日 午前10時34分
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