Part 1 - Gener
al In
forma
tion
Amazon Unitario Top Discharge
13
c) Find the correction factor for piping length and level difference (“K1”)
Figure 1-5.3: Amazon Unitario Top Discharge rate of change in cooling capacity
90
-90
-100
-110
80
-80
70
-70
60
-60
50
-50
40
-40
30
-30
20
-20
10
10
1.
0
0.
97
0.
95
0.
92
0.
90
0.
87
0.
85
0.
84
0.
81
0.
80
0.
78
0.
78
0.
77
0.
76
1.
0
0.
97
0.
95
0.
92
0.
90
0.
87
0.
85
0.
84
0.
81
0.
80
0.
78
0.
78
0.
77
20 30 40 50 60 70 80
K1 = 0.898
90 100 110 120 130 140 150 160 170 180 190 200
-10
0
0
Notes:
1. The horizontal axis shows equivalent length of piping between farthest indoor unit and first
outdoor branch joint; the vertical axis shows the largest level difference between indoor
unit and outdoor unit. For level differences, positive values indicate that the outdoor unit
is above the indoor unit, negative values indicate that the outdoor unit is below the indoor
unit.
d) Calculate the corrected capacity of K2UF-560 DN4S-E (“C”) by using K1:
C = B × K1 = 60 × 0.898 = 53.8kW
The corrected capacity 53.8kW is larger than required total heat load 50.7kW, so selection is complete. (In the event
that the corrected capacity is lower than the required total heat load, Step 3 should be repeated from the point where
the outdoor unit capacity is provisionally selected.)
