55
IM CW500-02EN
Harmonic power Pk [W]
Range
Same as active power
Display digits
Same as active power
Display range
Same as active power
*
Percentage content 0.0% to 100.0% Percentage to the
absolute value of the fundamental waveform
Measurement
system
Complies with IEC61000-4-7
Accuracy
±0.3% rdg ± 0.2% rng + current clamp-on probe accuracy
(power factor 1, sine wave, 50/60 Hz)
* The sum value is the total value of all used channels.
Equation
Pc
k
=
V
c(10k)r
×A
c(10k)r
-
V
c(10k)i
×A
c(10k)i
Percentage content
1
100
c
ck
P
P
×
=
c: measurement channel, k: harmonic order,
r: real component after taking the FFT,
i: imaginary component after taking the FFT
The measurement interval of the above equation is 10 cycles.
For 12 cycles, replace “(10k)” with “(12k)”
in the equation.
1P2W-1 to 4
P
1k
,
P
2k
,
P
3k
,
P
4k
,
P
sumk
=
P
1k
+P
2k
+P
3k
+P
4k
1P3W-1, 2
P
1k
,
P
2k
,
P
sum1k
=
P
1k
+P
2k
P
3k
,
P
4k
,
P
sum2k
=
P
3k
+P
4k
P
sumk
=
P
sum1k
+P
sum2k
3P3W-1, 2
P
1k
,
P
2k
,
P
sum1k
=
P
1k
+P
2k
P
3k
,
P
4k
,
P
sum2k
=
P
3k
+P
4k
P
sumk
=
P
sum1k
+P
sum2k
3P3W3A
Phase voltage
P
1k
:
V
1
= ( V
12
-
V
31
)
/
3
,
P
2k
:
V
2
= ( V
23
-
V
12
)
/
3
,
P
3k
:
V
3
= ( V
31
-
V
23
)
/
3
,
P
sumk
=
P
1k
+P
2k
+P
3k
3P4W
P
1k
,
P
2k
,
P
3k
,
P
sumk
=
P
1k
+P
2k
+P
3k
Specifications