I
I
I
I
A
s
CTs
CTp
50
50
10459
1
9000
1 162
=
×
=
×
=
.
EQUATION14059 V1 EN
(Equation 69)
∠
I
50s
= 0º
frequency of
I
50s
= 50 Hz
It
I
I
I
A
fs
CTs
CTp
tf
=
×
=
×
=
10459
1
9000
1 162
.
EQUATION14062 V1 EN
(Equation 70)
∠
I
tfs
= 0º
frequency of
I
tf
= 50 Hz
•
Check that the service values (VOLTAGE, CURRENT, R(%), X(%)) are according
to the injected quantities and that ROTORANG is close to 0 rad. For this particular
injection the service values are:
•
VOLTAGE= 6.49 kV
•
CURRENT= 20918 A
•
R= –0.32%
•
X=–32.57%
•
ROTORANG= 0.08 rad
Note that these values identify a point outside the lens characteristic, even if it is close
to the point SE. Neither START nor TRIP is issued.
Execution of the dynamic test
The test may be performed by using two states of a sequence tool that is a basic feature of
test sets.
•
State 1: pre-test condition.
Steady voltage and current are applied in order to get a steady high impedance, that
is, a point in the plane R-X which is far away from the lens characteristic. Define the
following three-phase symmetrical quantities (the phase angle is related to phase L1):
V
V
V
V
V
ts
t RvsZ
VT s
VT p
=
×
×
=
×
×
=
1 1
1 1 5899
0 1
13 8
47 02
.
.
.
.
.
,
,
,
EQUATION14069 V1 EN
(Equation 71)
29.60
arctan
180
arctan
180
90.56
0.29
ts
ReverseX
V
ReverseR
Ð
=
-
° =
-
° = -
°
æ
ö
æ
ö
ç
÷
ç
÷
è
ø
è
ø
EQUATION14068 V1 EN
(Equation 72)
frequency of V
ts
= 50 Hz
I
50s
= 0 A
Section 11
1MRK 511 366-UUS -
Testing functionality by secondary injection
120
Commissioning manual
Содержание RES670 2.1
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