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tion for an external signal to the switches “external”
positions.

The FM and PM switches provide VCG inputs. The AM
switch controls the control amplifier and thus the
transconductance multiplier. When AM is off, the con-
trol amplifier produces a positive dc level giving the

multiplier a fixed gain. With internal AM, the dc com-
ponent from the control amplifier is cut in half, halving
the output amplitude to prevent output clipping when
modulating. The selected  modulation waveform rides
on the dc. The ac (modulation signal) has a peak value
equal in magnitude to the dc level when the modula-
tion amplitude control is maximum, making the sum of
modulator and carrier signals equal to the maximum

output capability of the output amplifier, and the differ-
ence equal to the zero output level, which is 1 0 0 %
modulation. Then, by varying the modulation signal, a
variable 0 to 100% AM of the carrier (main generator)
signal is produced. With external AM, the dc compo-
nent is switched to 0 Vdc, resulting in zero amplitude
output, and bipolar signal inputs at the EXT MOD IN
connector will produce suppressed carrier (4-quadrant)
modulation.

4.2

CIRCUIT ANALYSIS

4.2.1 VCG Amplifier

Figure 4-3 is a simplified schematic of the VCG  cir-

cuitry. The value of a resistor “R” is 5 

and supplies

are

15 Vdc. U1 is connected as a summing

amplifier to sum the VCG inputs. A top of range input
produces 1mA through the feedback resistor resulting
in - 5 Vdc at the output of  U1

The negative input of U4 is held at the output level of

U1 by controlling the current through Q2 as a feed-
back. One half the output of U1 is buffered by U3 and
applied to the wiper of the variable symmetry control.

The negative input of U2 is held at 0 Vdc by controlling
the current through Ql as a feedback. As long as the
variable symmetry control is off, the two R/2 resistors

have equal voltage across them and an equal current
through them as through U1 feedback and there is no
current at the output of U3. Since an equal current
exists in the entire resistor string from + to - supply,
the result is a positive control voltage relative to the
negative supply at U6 + input and a negative control
voltage  with respect to the positive supply at U5 + in-
put, each of which is proportional to the sum of the in-
puts to U1

Similarly, U5 and U6 establish feedback by regulating
current through FETs, producing a voltage drop

across series resistors to the supplies equal to the
control voltages. The FET currents will be switched at
the diode gate into a timing capacitor to produce the
triangle waveform.

4.2.2

Symmetry Control

Let the source of Q2 be - 5 Vdc, the wiper of the sym-
metry control, - 2.5 Vdc, and the source of Q1, 0 Vdc.

The output of U3 will have no current, each R/2 resis-
tor will have  1 mA, and generator frequency will be at

maximum of the range. Open the symmetry switch
and set the potentiometer to its electrical center. The
output of U3 is still at an equipotential point, but now
the total resistance with 5 Vdc across it has changed
from R to 10R. Thus, current will drop to 100

 and

output frequency will drop to one-tenth of range. If the
potentiometer is rotated, current will flow in U3 output
to maintain the wiper at - 2.5 Vdc. When the potentio-
meter is ccw, the wiper is at the positive direction and
the upper R/2 will have 2.5V across it with a current
source of 1 mA. But the lower R/2 is in series with  9R,
which puts 2.5V  across 19

x

the normal resistance.

Now the current sink will have one-nineteenth the

magnitude of the current source. The output waveform
for this condition is shown in figure 4-3. Regardless of
where the symmetry control is rotated, frequency
stays the same (one-tenth of range).

4.2.3

Range Switching

For frequency ranges associated with multiplier posi-

tions of 100 and 1 K, main board schematic, sheet 1,
the value of the current source and current sink setting

resistors R326, R38, R48 and R330 is 5 

 which pro-

vides integrating current sensitivity of 200

 per volt

of external FM input. With the timing capacitors of 1
and 0.1 

 plus the bulk of the top range timing capa-

citor and the stray capacitance of the multiplier switch,
the generator produces the calibrated output fre-
quency for these ranges. In the top range (multiplier
position of 10M), the current setting resistors are
paralleled with resistors of one-ninth the value, caus-
ing both current sources to run at ten times the usual
current, resulting in 2 mA per volt of external FM input.
When this current is used with the nominal -90 pF
timing capacitor (fixed value plus strays), the top
range of frequencies result. For the next three ranges
down (multiplier positions  1 M, 100K, 10K), the nominal
timing capacitor is the fixed top range capacitor plus
strays (i.e., -90 pF) plus the switched values (11 pF,

9 1 0 pF, 0.01

These result in joint timing

capacitors of 101 pF, 1010 pF and 0.0101 

 In these

three ranges the positive and negative current
sources are boosted by 1 

 over the next range down

4-3

Summary of Contents for 148A

Page 1: ...NS INFORMATION PRO PRIETARY TO WAVETEK AND IS SOLELY FOR IN STRUMENT OPERATION AND MAINTENANCE THE INFORMATION IN THIS DOCUMENT MAY NOT BE DUPLICATED IN ANY MANNER WITHOUT THE PRIOR APPROVAL IN WRITIN...

Page 2: ...r is quiescent until trig gered by an external signal then generates one cycle at the selected frequency External Gate Same as external trigger except gen erator oscillates at the selected frequency f...

Page 3: ...m Inoperative at frequency multiplier settings below 100 Input frequencies roll off at 6 dB octave above one half of full range frequency and above 150 kHz Input impedance is IO 1 2 1 4 Frequency Rang...

Page 4: ...1 2 2 2 Frequency Range 0 1 Hz to 100 kHz in three 100 1 ranges Sweep 0 2 Hz to 200 kHz 2 x setting and are fixed level 10V p p balanced about ground M and M are fixed level 5 Vp from 0 to 5V 1 2 2 4...

Page 5: ...is quiescent until a proper gate signal is applied at the EXTTRIG IN BNC 13 and then outputs the selected signal for the duration of the gate signal plus the time to complete the last cycle generated...

Page 6: ...red One cycle of waveform for each trigger signal C Gated A burst of waveforms for the dura tion of each gate signal d AM The instantaneous amplitude of the out put signal varies with the instantaneou...

Page 7: ...r gating the generator For manually triggering single cycles the generator mode should be EXT TRIG with no external signal in put at the EXT TRIG IN connector Each time TRIG GER LEVEL is rotated cw th...

Page 8: ...ing decreases and the angle subtended in the nomograph decreases If the MOD AMPLITUDE control is rotated toward MAX the angle subtended would overshoot the OUTPUT FREQUENCY FACTOR range indicating tha...

Page 9: ...red One cycle of waveform for each trigger signal C Gated A burst of waveforms for the dura tion of each gate signal d AM The instantaneous amplitude of the out put signal varies with the instantaneou...

Page 10: ...r gating the generator For manually triggering single cycles the generator mode should be EXT TRIG with no external signal in put at the EXT TRIG IN connector Each time TRIG GER LEVEL is rotated cw th...

Page 11: ...ing decreases and the angle subtended in the nomograph decreases If the MOD AMPLITUDE control is rotated toward MAX the angle subtended would overshoot the OUTPUT FREQUENCY FACTOR range indicating tha...

Page 12: ...per Limit 2 0 x FREQ MULT Lower Limit 0 001 X Upper Limit Nominally the phase of the main generator is shifted ten degrees for each volt of instantaneous modulation signal When the main generator is s...

Page 13: ...and the hysteresis switch goes to 2V This switches currents at the diode gate and the negative going triangle slope is started When the triangle reaches the 1 25V limit the hysteresis switch will swit...

Page 14: ...con tinuous independent of generator mode While the integrating capacitor is being held from charging the start stop diode must sink the current source which has a magnitude variable with VCG in puts...

Page 15: ...across series resistors to the supplies equal to the control voltages The FET currents will be switched at the diode gate into a timing capacitor to produce the triangle waveform 4 2 2 Symmetry Contr...

Page 16: ...R 9 VERNIER I R 2 1 R SYMMETRY R R 2 OM R 9 Figure 4 3 VCG Simplified Schematic...

Page 17: ...th output impedance low enough to drive the hyster esis switch and the triangle buffer In series with Q8 is a matched duplicate FET Q9 Q9 has the identical drain current as Q8 and therefore the same g...

Page 18: ...circuit In the positive pulse mode the square wave rather than the triangle wave is fed to the circuit and the 15 volt power is switched off As a result the negative swing of the input square wave is...

Page 19: ...ter current The result is that the voltage at point B I N P U T U 19 Q37 Q38 r which is the output voltage will start to go negative Finally when the output has moved far enough negative to pull point...

Page 20: ...ve than the trigger level is 4 8 clipped by forward biasing CR1 the negative portion is clipped by CR2 While CR1 is on Q1 conducts and Q3 switches off to a TTL low level While CR2 is on Q1 is off and...

Page 21: ...erefore R64 will have the same voltage across it as the drop across CR2 The current leaving Q7 enters the trigger amplifier summing node and becomes a voltage offset equal to the drop across CR2 becau...

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