6.2.1 Calibration example
Calibrating a front end loader with a bucket capacity of 1.5 tonnes.
1. Set the calibration factor initially to 1.500.
2.
A bucket load is weighed and the Weighlog reading is 1.15 tonnes. The same
load is weighed on the weigh scales and the true weight is 0.850 tonnes.
3.
Using the correction calculation :
Correct factor = existing factor x true weight
Weighlog reading
= 1.50 x 0.850
1.15
= 1.1087
4.
Re-program with a factor of 1.109
So, if the Weighlog reading is more than the true weight, the factor is
decreased and vice versa, if the Weighlog reading is less than the true
weight, the factor is increased.
Therefore, if you find a consistent discrepancy between the Weighlog
readings and the weighbridge readings, intuitively, you can then nudge the
cal factor up or down as required
E.g. If the Weighlog reading is 10% high, then reduce the cal. factor by 10%.
6 - Calibration
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