GREE GMV5E DC INVERTER VRF UNITS SERVICE MANUAL
71
(1) Method for calculating the quantity of refrigerant perfused for the pipe (A):
Quantity of perfused refrig
erant for the pipe (A) = ∑ Length of the liquid pipe x Quantity of perfused
refrigerant for the liquid pipe per meter
Diameter of the Liquid Pipe
Φ28.6
Φ25.4
Φ22.2
Φ19.05
Φ15.9
Φ12.7
Φ9.52
Φ6.35
kg/m
0.680
0.520
0.350
0.250
0.170
0.110
0.054
0.022
(2) Method
for calculating ∑ for the quantity of refrigerant perfused for each module (B)
Refrigerant charging amount B of every module(kg)
②
Module capacity(kW)
IDU/ODU rated capacity
collocation ratio C
①
Quantity of
included IDUs
22.4
28.0
33.5
40.0
45.0
50.4
56.0
61.5
50%≤C≤70%
<4
0
0
0
0
0
0
0
0
≥4
0.5
0.5
0.5
0.5
0.5
0.5
1.0
1.5
70%<
C≤90%
<4
0.5
0.5
1.0
1.5
1.5
1.5
2.0
2.0
≥4
1.0
1.0
1.5
2.0
2.0
2.5
3.0
3.5
90%<
C≤105%
<4
1.0
1.0
1.5
2.0
2.0
2.5
3.0
3.5
≥4
2.0
2.0
3.0
3.5
3.5
4.0
4.5
5
105%<
C≤135%
<4
2.0
2.0
2.5
3.0
3.0
3.5
4.0
4.0
≥4
3.5
3.5
4.0
5.0
5.0
5.5
6.0
6.0
Note:
①
IDU/ODU rated capacity collocation ratio C = Sum of rated cooling capacity of indoor unit / Sum
of rated cooling capacity of outdoor unit
②
If all of the indoor units are fresh air indoor units, the quantity of refrigerant added to each module
is 0kg.
③
If outdoor air processor is connected with normal VRF indoor unit, adopt the perfusion method
for normal indoor unit for perfusion.
For example1:
Outdoor unit consists of one 28kW module and one 45kW module. Five 14kW duct type units are
used as indoor units.
IDU/ODU rated capacity collocation ratio C= 140×5/ (280+450) =96%. The quantity of included
IDUs is more than 4 sets. Please refer to the above table.
Additional refrigerant quantity B for 28kW module is 2.0kg.
Additional refrigerant quantity B for 45kw module is 3.5kg.
So, ∑Refrigerant charging amount B of every module=2.0+3.5=5.5kg
Suppose the Pipeline charging amount A=∑Liquid pipe length×refrigerant charging amount of every
1m liquid pipe=20kg
Total refrigerant charging amount R=20+5.5=25.5kg
For example 2:
Outdoor unit is a 45kW module and the indoor unit is a 45kW fresh air unit. The quantity (B) of
refrigerant added to this module is 0kg.
So, ∑B (Quantity of refrigerant added to each module) = 0kg
Suppose that A (Quantity of refrigerant added to connection pipe) = ∑ Length of liquid pipe x
Quantity of refrigerant added to liquid pipe per meter) = 5kg
R (Quantity of added refrigerant in total) = 5+0=5kg
