DMC-1500
Chapter 10 Theory of Operation
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137
Then the corresponding time constants are
Tm = 0.04 sec
and
Te = 0.002 sec
Assuming that the amplifier gain is Kv = 4, the resulting transfer function is
P/V = 40/[s(0.04s+1)(0.002s+1)]
Current Drive
The current drive generates a current I, which is proportional to the input voltage, V, with a gain of
Ka. The resulting transfer function in this case is
P/V = Ka Kt / Js2
where Kt and J are as defined previously. For example, a current amplifier with Ka = 2 A/V with the
motor described by the previous example will have the transfer function:
P/V = 1000/s2 [rad/V]
If the motor is a DC brushless motor, it is driven by an amplifier that performs the commutation. The
combined transfer function of motor amplifier combination is the same as that of a similar brush
motor, as described by the previous equations.
Velocity Loop
The motor driver system may include a velocity loop where the motor velocity is sensed by a
tachometer and is fed back to the amplifier. Such a system is illustrated in Fig. 10.5. Note that the
transfer function between the input voltage V and the velocity
ω
is:
ω
/V = [Ka Kt/Js]/[1+Ka Kt Kg/Js] = 1/[Kg(sT1+1)]
where the velocity time constant, T1, equals
T1 = J/Ka Kt Kg
This leads to the transfer function
P/V = 1/[Kg s(sT1+1)]
Σ
K
a
Kt/Js
K
g
V
Figure 10.5 - Elements of velocity loops
The resulting functions derived above are illustrated by the block diagram of Fig. 10.6.
Summary of Contents for DMC-1510
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Page 18: ...6 Chapter 1 Overview DMC 1500 THIS PAGE LEFT BLANK INTENTIONALLY...
Page 88: ...76 Chapter 6 Programming Motion DMC 1500 Figure 6 7 Motion intervals in the Home sequence...
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Page 137: ...DMC 1500 Chapter 7 Application Programming 125 THIS PAGE LEFT BLANK INTENTIONALLY...
Page 157: ...DMC 1500 Chapter 10 Theory of Operation 145 THIS PAGE LEFT BLANK INTENTIONALLY...
Page 160: ...148 Appendices DMC 1500 Card Level Layout...
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