35
TGH 1360E
Analog output IR5002 (0-20 mA)
1 k
Ω
is 100
µ
A
Calculating
formula
IR5002
0
.
7
0
3
1
5
.
7
5
2
1
0
.
8
0
2
1
5
.
8
5
1
1
0
.
9
0
1
1
5
.
9
5
0
1
0
.
0
1
0
0
1
5
.
0
1
5
9
0
.
1
1
0
9
5
.
1
1
5
8
0
.
2
1
0
8
5
.
2
1
5
7
0
.
3
1
0
7
5
.
3
1
5
6
0
.
0
0
0
2
5
.
0
5
9
1
0
.
1
0
9
1
5
.
1
5
8
1
0
.
2
0
8
1
5
.
2
5
7
1
0
.
3
0
7
1
5
.
3
5
6
1
0
.
4
0
6
1
5
.
4
5
5
1
0
.
5
0
5
1
5
.
5
5
4
1
0
.
6
0
4
1
5
.
6
5
3
1
0
.
4
1
0
6
5
.
4
1
5
5
0
.
5
1
0
5
5
.
5
1
5
4
0
.
6
1
0
4
5
.
6
1
5
3
0
.
7
1
0
3
5
.
7
1
5
2
0
.
8
1
0
2
5
.
8
1
5
1
0
.
9
1
0
1
5
.
9
1
5
0
.
0
2
0
I/mA Rf/k
Ω
I/mA Rf/k
Ω
Current
resistance table
Diagram: current output 0 … 20 mA
Diagram
current output
IR5002
I/mA Rf/k
Ω
Analog output
IR5002
The IR5002 provides one analog output of 0…20 mA which is specified in the
table below:
0
50
100
150
200
250
I / mA
Rf / KOhm
0.0
2.0
10.0
12.0
4.0
8.0
6.0
16.0
14.0
20.0
18.0
Rf [k
Ω
] = -10*I [mA] + 200
