Dielectric
constant
and
dissipation
factor
of
a
test
material
can
be
obtained
using
the
following
equations
.
P
arameters
Needed:
C
p
Equivalent
parallel
capacitance
[F]
D
Dissipation
factor
t
a
A
verage
thickness
of
test
material
[m]
A
Area
of
Guarded
electrode
[m
2
]
d
Diameter
of
Guarded
electrode
[m]
(38210
-3
[m]
or
5210
-3
[m])
o
=8.854210
-12
[F/m]
Equations:
r
=
t
a
2
C
p
A
2
o
=
t
a
2
C
p
2
d
2
2
2
o
D
t
=
D
Where
,
r
Dielectric
constant
of
test
material
D
t
Dissipation
factor
of
test
material
3-12
Operation
Summary of Contents for 16451B
Page 8: ... C Copyright 2008 Agilent Technologies ...
Page 10: ......
Page 20: ......
Page 28: ......
Page 34: ......
Page 46: ......
Page 56: ...Figure 3 6 Summary of Measurement Methods 3 10 Operation ...
Page 83: ...because a change of temperature causes mechanical dimensions to change Operation 3 37 ...
Page 119: ...Figure 4 4 Cable Connection Diagram Service 4 9 ...
Page 120: ......
Page 122: ......
Page 132: ......
Page 138: ......