7-79
Calculation example 3
When all but one station have been added to a 16-unit link, the largest station number is 16, relays and
registers have been allocated evenly, and the scan time for each PLC is 5 ms.
Ttx = 0.096 Each Ts = 5 + 6.82 = 11.82 ms
Tlt = 0.096 x (13 + 2 x 15)
≒
4.13 ms
Tlk = 0.96 + 400 + 0.67 + 5
≒
407 ms
Note: The default value for the addition waiting time is 400 ms.
Given the above conditions, the maximum value for the transmission time (T) of one cycle will be:
T max. = 11.82 x 15 + 4.13 + 5 + 407 = 593.43 ms
Calculation example 4
When all stations have been added to an 8-unit link, the largest station number is 8, relays and register
have been evenly allocated, and the scan time for each PLC is 5 ms.
Ttx = 0.096 Each Pcm = 23 + (8 + 16) x 4 = 119 bytes
Tpc = Ttx x Pcm = 0.096 x 119
≒
11.43 ms
Each Ts = 5 + 11.43 = 16.43 ms Tlt = 0.096 x (13 + 2 x 8)
≒
2.79 ms
Given the above conditions, the maximum value for the transmission time (T) of one cycle will be:
T max. = 16.43 x 8 + 2.79 + 5 = 139.23 ms
Calculation example 5
When all stations have been added to a 2-unit link, the largest station number is 2, relays and registers
have been evenly allocated, and the scan time for each PLC is 5 ms.
Ttx = 0.096 Each Pcm = 23 + (32 + 64) x 4 = 407 bytes
Tpc = Ttx x Pcm = 0.096 x 407
≒
39.072 ms
Each Ts = 5 + 39.072 = 44.072 ms Tlt = 0.096 x (13 + 2 x 2)
≒
1.632 ms
Given the above conditions, the maximum value for the transmission time (T) of one cycle will be:
T max. = 44.072 x 2 + 1.632 + 5 = 94.776 ms
Calculation example 6
When all stations have been added to a 2-unit link, the largest station number is 2, 32 relays and 2
register words have been evenly allocated, and the scan time for each PLC is 1 ms.
Ttx = 0.096 Each Pcm = 23 + (1 + 1) x 4 = 31 bytes
Tpc = Ttx x Pcm = 0.096 x 31
≒
2.976 ms
Each Ts = 1 + 2.976 = 3.976 ms Tlt = 0.096 x (13 + 2 x 2)
≒
1.632 ms
Given the above conditions, the maximum value for the transmission time (T) of one cycle will be:
T max. = 3.976 x 2 + 1.632 + 1 = 10.584 ms
Note:
•
In the description, “stations that have been added” refers to stations which are connected between
station no. 1 and the largest station number and for which the power supply has been turned on.
•
Comparing examples 2 and 3, the transmission cycle time is longer if there is one station that has not
been added to the link. As a result the PC(PLC) link response time is longer.
•
The SYS1 instruction can be used to minimize thte transmission cycle time even if there are one or
more stations that have not been added to the link.
Содержание FP E Series
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Страница 17: ...Chapter 1 Functions and Restrictions of the Unit ...
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Страница 29: ...Chapter 2 Specifications and Functions of the Unit ...
Страница 37: ...2 9 Circuit diagram C32 Y0 Y1 Y3 Y4 C28 Y0 Y1 Y3 Y4 Y2 Y5 to YF Y2 Y5 to YB ...
Страница 48: ...2 20 ...
Страница 49: ...Chapter 3 Expansion ...
Страница 56: ...3 8 Terminal layout diagram Note The numbers in the connector are for the first expansion ...
Страница 61: ...Chapter 4 I O Allocation ...
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Страница 67: ...Chapter 5 Installation and Wiring ...
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Страница 91: ...Chapter 6 High speed counter Pulse Output and PWM Output functions ...
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Страница 125: ...6 35 Pulse output diagram ...
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Страница 147: ...6 57 Program ...
Страница 151: ...Chapter 7 Communication Cassette ...
Страница 202: ...7 52 Procedure of communication In the following example the Micro Imagechecker is connected to COM1 port ...
Страница 210: ...7 60 The values of DT50 and DT51 are written in DT0 and 1 of PLC ...
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Страница 249: ...Chapter 9 Precautions During Programming ...
Страница 260: ...9 12 Example 2 Using the CT instruction between JP and LBL instructions ...
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Страница 269: ...Chapter10 Specifications ...
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Страница 287: ...Chapter 11 Dimensions ...
Страница 290: ...11 4 11 1 3 Expansion Unit FPG XY64D2T FPG XY64D2P FPG EM1 ...
Страница 293: ...Chapter 12 Appendix ...
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