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V6-i VRF 50Hz
19
P
art 1
- G
ener
al
In
forma
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n
c)
Find the correction factor for piping length and level difference (“K1”)
Figure 1-5.4: V6-i rate of change in cooling capacity
Notes:
1.
The horizontal axis shows equivalent length of piping between farthest indoor unit and outdoor
unit; the vertical axis shows the largest level difference between indoor unit and outdoor unit.
For level differences, positive values indicate that the outdoor unit is above the indoor unit,
negative values indicate that the outdoor unit is below the indoor unit.
d)
Calculate the corrected capacity of MVi-280WV2RN1(A) (“C”) by using K1:
C = B × K1 = 30.01 × 0.898 =26.95kW
The corrected capacity 26.95 kW is larger than required total heat load 26.5kW, so selection is complete.
50
40
-40
30
-30
20
-20
10
1
.0
0
.9
7
0.9
5
0
.9
2
0
.9
0
0.
87
0
.8
5
0.
84
0
.8
1
1.0
0.
97
0.
95
0
.9
2
0
.9
0
0.
87
0
.8
5
0
.8
4
10 20 30 40 50 60 70 80 90 100 110 120
-10
0
0
L(m)
H(m)