V6-i VRF 50Hz
17
P
art 1
- G
ener
al
In
forma
tio
n
c)
Find the correction factor for piping length and level difference (“K1”)
Figure 1-5.3: V6-i rate of change in cooling capacity
Notes:
1.
The horizontal axis shows equivalent length of piping between farthest indoor unit and first
outdoor branch joint; the vertical axis shows the largest level difference between indoor unit
and outdoor unit. For level differences, positive values indicate that the outdoor unit is above
the indoor unit, negative values indicate that the outdoor unit is below the indoor unit.
d)
Calculate the corrected capacity of MVi-260WV2RN1(A) (“C”) by using K1:
C = B × K1 = 27.59 × 0.898 =24.77kW
The corrected capacity 24.77 kW is lower than required total heat load 26.5kW, so selection is not complete. Step 3
should be repeated from the point where the outdoor unit capacity is provisionally selected.
Repeat Step 3: Select outdoor unit
Determine the required total heat load from the indoor units to the outdoor unit based on either the sum of the peak
loads of each room or the system peak load. In this example, it is determined based on the system peak load. Therefore,
the required heat load is 26.5kW.
Provisionally select an outdoor unit using the sum of the capacity indexes (CIs) of the selected indoor units (as shown
in Table 1-5.4), ensuring that the combination ratio is between 50% and 130%. Refer to Table 1-5.5. As the sum of CIs
of the indoor units is 314, outdoor units 9-16HP are potentially suitable. For the 9HP unit is not suitable, try to select
10HP unit.
Table 1-5.8: Sum of indoor unit capacity indexes
Model
Capacity Index No. of units
MI2-112T2DHN1
112
1
MI2-56T2DHN1
56
2
MI2-45T2DHN1
45
2
Sum of CIs
314
50
40
-40
30
-30
20
-20
10
1
.0
0
.9
7
0.9
5
0
.9
2
0
.9
0
0.
87
0
.8
5
0.
84
0
.8
1
1.0
0.
97
0.
95
0
.9
2
0
.9
0
0.
87
0
.8
5
0
.8
4
10 20 30 40 50 60 70 80 90 100 110 120
-10
0
0
L(m)
H(m)
