I-7530, I-7530A, I-7565, I-7530-FT, tM-7530, tM-7530A, tM-7565 User Manual Version 1.6
Page:
95
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If we fix (4 + PRS + PHS1 + PHS2) to 20, the BRP value is:
T
bit
/ (BRP + 1) = (4 + PRS + PHS1 + PHS2) * TQ
500 / (BRP + 1) = 20
500 / 20 = (BRP + 1) = 25
BRP = 24
3. Find the values of PRS, PHS1 and PHS2 using the sampling points. If it is assumed
that the sampling point is 60%, and (4 + PRS + PHS1 + PHS2) in step 2 is fixed to
20, then:
取樣點的取樣比例
= (3 + PRS + PHS1) / (4+PRS+PHS1+PHS2)
60% = (3 + PRS + PHS1) / 20
12 = (3 + PRS + PHS1)
Among them, since the maximum value of PRS, PHS1, and PHS2 in the register is
7, if it is assumed that PHS1 is 7, it can be known that PRS is 2, as below formula.
12 = (3 + PRS + PHS1)
PRS = 12 - 3 - 7
PRS = 2
Next, since (4 + PRS + PHS1 + PHS2) is fixed at 20, it can be known that PHS2 is
7, as below formula.
(4 + PRS + PHS1 + PHS2) = 20
PHS2 = 20 - 4 - 2
– 7
PHS2 = 7