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Page 13-19
The last four steps show the progression of the solution: a square root,
followed by a fraction, a second fraction, and the final result. This result can
be simplified by using function
@SIMP
, to read:
Integration by parts and differentials
A differential of a function y = f(x), is defined as dy = f’(x) dx, where f’(x) is
the derivative of f(x). Differentials are used to represent small increments in
the variables. The differential of a product of two functions, y = u(x)v(x), is
given by dy = u(x)dv(x) +du(x)v(x), or, simply, d(uv) = udv - vdu. Thus, the
integral of udv = d(uv) - vdu, is written as
∫
∫
∫
−
=
vdu
uv
d
udv
)
(
. Since by
the definition of a differential,
∫
dy = y, we write the previous expression as
∫
∫
−
=
vdu
uv
udv
.
This formulation, known as integration by parts, can be used to find an
integral if dv is easily integrable. For example, the integral
∫
xe
x
dx can be
solved by integration by parts if we use u = x, dv = e
x
dx, since, v = e
x
. With
du = dx, the integral becomes
∫
xe
x
dx =
∫
udv = uv -
∫
vdu = xe
x
-
∫
e
x
dx = xe
x
- e
x
.
The calculator provides function IBP, under the CALC/DERIV&INTG menu, that
takes as arguments the original function to integrate, namely, u(X)*v’(X), and
the function v(X), and returns u(X)*v(X) and -v(X)*u’(X). In other words,
function IBP returns the two terms of the right-hand side in the integration by
parts equation. For the example used above, we can write in ALG mode:
Содержание 48GII
Страница 1: ...hp 48gII graphing calculator user s guide H Edition 4 HP part number F2226 90020 ...
Страница 162: ...Page 3 37 Define this function by any of the means presented above and check that g 3 3 g 1 0 g 1 0 g 3 9 ...
Страница 201: ...Page 5 30 LIN LNCOLLECT POWEREXPAND SIMPLIFY ...
Страница 381: ...Page 11 55 Function KER Function MKISOM ...
Страница 461: ...Page 13 26 In the right hand side figure above we are using the line editor to see the series expansion in detail ...
Страница 777: ...Page 26 8 ...
Страница 840: ...Page L 5 ...