Determine correction factor
Ambient temperature
T
U
°C
≤ 40
Correction factor
k
TU
1
Installation height amsl
≤ 1000 m
≤ 2000 m
≤ 3000 m
≤ 4000 m
Correction factor
k
H
k
H
k
H
k
H
1
0.95
.90
.85
Determine product on the basis of the forces
Transmission element
Gear wheels
Sprockets
Toothed belt pulleys
Narrow V-belt
(depending on the
pretension)
(depending on the
pretension)
Additional radial force factor f
Z
≥ 17 teeth: 1.0
≥ 20 teeth: 1.0
With belt tightener: 2.0 –
2.5
1.5 – 2.0
< 17 teeth: 1.15
< 20 teeth: 1.25
Without belt tightener: 2.5
– 3.0
< 13 teeth: 1.4
Calculation
Check
Radial force
F
rad
N
´
=
´
L,max
z
rad
M
f
F
2000
dw
F
rad
≤ f
W
x F
rad,max
Axial force
F
ax
N
F
ax
≤ F
rad,max
x 0.5
dw
Effective diameter of transmission element in mm
f
W
Additional load factor
Radial forces and axial forces
Calculate output torque
Calculation
Necessary output torque
M
2
N
m
³
´
L,max
2
H
TU
M
M
k
k
Calculate intensity
Calculation
Intensity
F
I
+
+ +
=
£
+ +
L
M
B
Z
2
I
M
B
Z
J
J
J
J
i
F
1.25
J
J
J
i
Ratio of gearbox
J
B
Moment of inertia of brake
J
L
Moment of inertia of the load
J
Z
Additional moment of inertia (handwheel, 2nd shaft end ...)
J
M
Moment of inertia of motor
Determine the product on the basis of the data obtained from the selection tables
Selection table
Check
Output speed n
2
rpm
n
L,max
≈ n
2
Output torque M
2
Nm
M
L,max
≤ M
2
Information on project planning
Drive dimensioning
22
Содержание g500-H
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