Husqvarna SM 610 2006, Руководство по ремонту, Страница: 34 / 230

1 0
S E T T IN G S A N D A D J U S T M E N T S
C lu tc h a d ju s tm e n t
T h e co n tro l Ie ve r m u st h a ve a 0 .1 2 ÷ 0 .2 0 in . id le stro ke b e fo re b e g in n in g to d ise n g a g e
th e clu tch . T o a d ju st th is sla ck, re m o ve th e ru b b e r ca p (1 ), L o o se n th e lo ck n u t (2 ) a n d
o p e ra te th e a d ju ste r (3 ). T h e sla ck d e cre a se s w h e n u n scre w in g , a n d in cre a se s w h e n
scre w in g . T a ke ca re to tig h te n p ro p e rly th e Io ck n u t. If d ifficu ltie s a rise in re a ch in g th e
o p tim u m va lu e , tu rn a d ju ste r Io ca te d o n th e cra n kc a se .
In ca se th e clu tch d isk w e re re p la ce d , clu tch sh a ll b e a d ju ste d a s fo llo w s:
- S e t th e clu tch ro d (4 ) in th e slo t o f th e p rim a ry sh a ft th e n , se t th e th ru st cu p (5 ) w ith
th e b a lI e n g a g e d (6 );
- S e t th e clu tch Ie ve r ke e p in g a d ista n ce L = 4 .3 5 ÷ 4 .4 3 in ., o n th e c ra n kca se (F IG U R E
1 ).
In sta ll th e frictio n d isk (7 ). P u t first a Iin e d d isk, th e n a lte rn a tive ly a n o n lin e d d isk w ith a
Iin e d d isk. T o ta l q u a n tity is e ig h t Iin e d d isks w ith se ve n n o n -Iin e d d isks;
- In sta ll th e b e a rin g (8 ), th e w a sh e r (9 ), d isk th ru st p la te (1 0 ) w ith six sp rin g s a n d re la -
tive b o lts (1 1 ). T ig h te n to a to rq u e va lu e o f 7 ,3 ft-Ib .;
- A lig n th e in d e x m a rk b e tw e e n th e d isk th ru st p la te a n d th e th ru st cu p . U sin g a fla t
scre w d rive r o n th e scre w (a ), tig h te n th e ja m n u t (b );
- R e in sta ll th e clu tch co ve r (tig h te n in g to rq u e : 9 ,3 N m / 0 ,9 5 K g m / 6 .9 ft-lb ), fill w ith th e
n e ce ssa ry q u a n tity o f o il (se e p a g e A .8 ) a n d ch e ck th e o il le ve l;
- A d ju st th e cle a ra n ce o f th e co n tro l Ie ve r p la ce d o n th e h a n d le b a r.
A : T o d e cre a se cle a ra n ce
B : T o in cre a se cle a ra n ce
L = 1 1 0 ,5 ÷1 1 2 ,5 m m
(4 .3 5 ÷ 4 .4 3 in .)