Applications—
Type
535A
Fig.
3-4. Measuring rhe frequency of a repetitive input signal.
5.
Subtract the first
DELAY TIME MULTIPLIER control setting
from the
second and multiply the result by the setting of
the
Time
Base B
TIME/CM control. The figure obtained is the
time interval
between the two events. The
figure obtained is
correct
regardless
of whether the magnifier is on or off.
Frequency
Measurements
Using
the methods described in the previous section, you
can
measure
the period
(time required for one cycle) of a
recurrent waveform. The frequency
of the waveform can
then
easily
be calculated since
frequency is the reciprocal
of
the period. For example, if the period of a recurrent
waveform
is
accurately measured and found to be 0.2 micro
seconds,
the frequency is the
reciprocal of 0.2 microseconds,
or
5
m
c.
At
any
given oscilloscope sweep rate, the number of
cycles
of
the
input waveform that
is displayed on 10 centi
meters
of the screen is dependent on the frequency of the
input
waveform. Frequencies can usually be measured faster
by
the following method than by
the one given in the last
paragraph.
If
you divide the cycles per unit of length by the time re
quired for
the
input waveform to sweep this unit of length,
you get the frequency. The
total number of cycles are found
for
10
cm
for
greater accuracy. Since the TIME/CM switch
gives time for 1 cm, multiply
this
setting by 10 to have
the time required
for 10 cm. (See Fig.
3-4.)
To
obtain
the frequency
of a repetitive input signal, per
form
the
following steps:
1.
Adjust
the TIME/CM
control to display several cycles of
the input
waveform. Insure
that the VARIABLE TIME/CM
control
is in the CALIBRATED position.
2.
Count
the
number of cycles of the waveform shown on
the 10 centimeters
of the graticule.
3.
Divide
this
number by 10 times
the TIME/CM switch set
ting.
This
gives you the frequency of the input waveform.
For
example,
assume that when you are using a sweep
rate
of 50
milliseconds
per centimeter, you count 7.2 cycles
in
10
centimeters.
The frequency is
7.2 cycles divided by 50
milliseconds
times 10,
or 500 milliseconds. 500 milliseconds
are 500 x .001
seconds,
or .5 seconds. 7.2 cycles per ½ sec
ond
gives
you 14.4 cycles per cycles per second.
3-4
Summary of Contents for 535A
Page 2: ......
Page 4: ...Type 535A ...
Page 28: ...Circuit Description Type 535A 4 2 Fig 4 1 Simplified Type 535A Vertical Amplifier ...
Page 30: ...Circuit Description Type 535A 4 4 Fig 4 2 Simplified Time Base Trigger Circuit ...
Page 32: ...Circuit Description Type 535A Fig 4 3 Simplified Time Base Generator 4 6 ...
Page 34: ...Circuit Description Type 535A 4 8 Fig 4 4 Simplified Delay Pickoff Circuit ...
Page 38: ...Circuit Description Type 535A Fig 4 6 Simplified Alternate Trace Operation Circuitry 4 12 ...
Page 39: ...Circuit Description Type 535A 4 13 ...
Page 41: ...Circuit Description Type 535A Fig 4 8 Simplified Low Voltage Power Supply 4 15 ...
Page 42: ...Circuit Description Type 535A 4 16 Fig 4 9 Simplified Calibrator Circuit ...
Page 44: ...Circuit Description Type 535A Fig 4 10 Simplified Cathode Ray Tube Circuit 4 18 ...
Page 126: ...MRU ll IG 61 O Z ...
Page 138: ...C897 R896 R891 R890 R889 R888 R887 R886 R885 AMPLITUDE CALIBRATOR SWITCH Bottom View 535A A ...
Page 143: ...FIG 1 FRONT SWITCHES TVDC COCA ocril I iCrODC ...
Page 144: ...70 ...
Page 145: ...1 FIG 3 SWEEP CHASSIS HIGH VOLTAGE BOARD DELAY SWEEP CHASSIS ...
Page 146: ...1 FIG 4 POWER CHASSIS RECTIFIER MOUNTING PLATE A ...
Page 147: ...3 34 79 ...
Page 148: ...TYPE 535A OSCILLOSCOPE ...
Page 149: ......
Page 150: ...FIG 7 CABINET FRAME RAILS ...
Page 152: ...FIG 8 STANDARD ACCESSORIES 6 TYPE 535A OSCILLOSCOPE ...
