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No
Label
Function
8
PUMP
Pump relay output
9
L1
Supply voltage
10
(not used)
11
L2
Supply voltage
12
(not used)
13
L3
Supply voltage
Choice and adaptation of current transformer
The pump motor size decides whether one or two current transformers shall be used. For
motor currents up to 100 A, one current transformer shall be used. From 100 to 1000 A
two transformers are needed.
0-100A
The current through the transformer should be close to its primary current rating, but
should not exceed it.
Current transformers with a choice of four ratings are available, i.e. 10A, 25A, 50A and
100A.
The phase conductor of the motor can be run through the current transformer core an
additional number of turns to put the available transformer capacity to full use.
The formula below can be used to determine how many turns the phase conductor of the
motor should be run through the transformer core.
Number = rated primary current of current transformer
of turns
rated motor current
(Round down to next lowest integer value).
Example 1:
Rated current of motor = 12 A
Primary current of current transformer = 25 A
Number of turns = 25 A/12 A
Answer = 2
Example 2:
Rated current of motor = 7.8 A
Primary current of current transformer = 10 A
Number of turns = 10 A/7.8 A
Answer = 1
100-1000A
If the rated motor current is in excess of the highest rated primary current of the available
transformers (100A), proceed as follows:
INSTALLATION
6
Single pump controller Installation and user manual for FPC100
Summary of Contents for FPC100
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