156
Then
CL
=200 * 95°52′11″*
180
=334.648 m
Tangent length
)
2
tan(
IA
R
TL
200 * tan(95°52′11″/ 2) =221.615 m
Each coordinates are computed:
2
2
cos
TL
N
N
IP
BC
2
2
sin
TL
E
E
IP
BC
3
2
cos
TL
N
N
IP
EC
3
2
sin
TL
E
E
IP
EC
Here:
2
(Bearing from IP1 to IP2) = 322°07′30.1″
3
(Bearing from IP2 to EP) = 57°59′40.6″
N
BC
1750 -
221.615 * cos322°07′30.1″ =1575.068 m
E
BC
1400 -
221.615 * sin322°07′30.1″ =1536.058 m
N
EC
1750
–
(-
221.615) * cos57°59′40.6″=1867.456 m
E
EC
1400
–
(-
221.615) * sin57°59′40.6″=1587.929 m
The calculated results display as below:
