
®
M o d e l N o . M E - 9 5 0 2
E x p . 1 1 B : M i n i m u m P e r i o d o f a P h y s i c a l P e n d u l u m
0 1 2 - 1 2 8 7 6 B
63
Exp. 11B: Minimum Period of a Physical Pendulum
Equipment Needed
Theory
The period of oscillation for a physical pendulum can be written as
follows:
where
I
is the moment of inertia (rotational inertia) for the physical
pendulum,
L
cm
is the perpendicular distance from the axis at the pivot
point to the parallel axis at the center of mass,
cm
, and
m
is the mass
of the pendulum.
The moment of inertia,
I
cm
, for a rectangular-type rod about its center
of mass is:
where
a
is the length and
b
is the thickness of the rectangular-type
rod. However, if the length,
a
, is much greater than the thickness,
b
,
then the following can be used as a very good approximation of the
moment of inertia around the center of mass:
where
m
is the mass and
L
is the length of the rod.
If the rod pivots around any other axis that is parallel to the axis through the center of mass, the Parallel Axis The-
orem states that the moment of inertia about the parallel axis,
I
parallel
, is the sum of the moment of inertia around
the center of mass,
I
cm
, plus
mL
cm
2
, where
m
is the mass of the rod and
L
cm
is the perpendicular distance from the
center of mass to the pivot point, or
The formula for the period of oscillation becomes
At what distance,
L
cm
, does the period of oscillation,
T
, become a
minimum
?
In this experiment you will determine the distance,
L
cm
, from the pivot point to the center of mass that gives the
minimum period of oscillation for the physical pendulum.
Item
Item
Statics Board
Balance Arm
Stopwatch (ME-1234)
Figure 11.5: Physical Pendulum
mg
mg sin
mg cos
Equilibrium
position
Pivot
point
Center of
mass
L
cm
T
2
I
L
cm
mg
-----------------
=
I
cm
1
12
------
m a
2
b
2
+
=
I
cm
1
12
------
mL
2
=
I
parallel
I
cm
mL
cm
2
+
1
12
------
mL
2
mL
cm
2
+
=
=
T
2
1
12
------
L
2
L
cm
2
+
L
cm
g
-------------------------------
=
Содержание ME-9502
Страница 1: ... PASCO Mechanics Statics System ME 9502 Instruction Manual 012 12876B 012 12876 ...
Страница 4: ... Statics System iv 012 12876B ...
Страница 20: ...Statics System Exp 2 Adding Forces Resultants and Equilibriants 16 012 12876B ...
Страница 24: ...Statics System Exp 3 Resolving Forces Components 20 012 12876B ...
Страница 28: ...Statics System Exp 4 Torque Parallel Forces 24 012 12876B ...
Страница 32: ...Statics System Exp 5A Center of Mass 28 012 12876B ...
Страница 36: ...Statics System Exp 5B Equilibrium of Physical Bodies 32 012 12876B ...
Страница 44: ...Statics System Exp 7 The Inclined Plane 40 012 12876B ...
Страница 50: ...Statics System Static Friction on an Inclined Plane 46 012 12876B ...
Страница 60: ...Statics System Exp 10 Simple Harmonic Motion The Simple Pendulum 56 012 12876B ...
Страница 66: ...Statics System Exp 11A Simple Harmonic Motion Physical Pendulum 62 012 12876B ...
Страница 70: ...Statics System Exp 11B Minimum Period of a Physical Pendulum 66 012 12876B ...
Страница 76: ...Statics System Exp 11C Simple Harmonic Motion Beam on a Spring 72 012 12876B ...
Страница 84: ...Statics System Exp 13 Simple Machines The Inclined Plane 80 012 12876B ...
Страница 94: ...Statics System Technical Support 90 012 12876B ...