
®
M o d e l N o . M E - 9 5 0 2
S l i d i n g F r i c t i o n o n a n I n c l i n e d P l a n e
0 1 2 - 1 2 8 7 6 B
43
Questions
1.
In trials 1 through 6, what happens to the sliding friction as the normal force increases?
2.
In trials 1 through 6, what happens to the coefficient of friction as the normal force increases?
3.
How does the sliding friction for the large wood surface compare to the sliding friction for the large felt sur-
face? How does the sliding friction for the small wood surface compare to the sliding friction for the small felt
surface?
4.
Based on your measurements, does the sliding friction between two objects depend on the materials that are in
contact?
5.
How does the sliding friction for the large wood surface compare to the sliding friction for the small wood
surface? How does the sliding friction for the large felt surface compare to the sliding friction for the small
felt surface?
6.
Based on your measurements, does the sliding friction between two objects depend on the area of contact
between the objects?
Sliding Friction on an Inclined Plane
If the Friction Block is not on a horizontal surface, will the
coefficient of sliding friction,
k
, be different?
When an object is on the Inclined Plane at an angle, one compo-
nent of the object’s weight (
F
= m
g
) is parallel to the surface of
the plane (F
), and another component of F is perpendicular to
the plane (F
. In theory, this perpendicular component is equal
to the normal force of the surface of the plane.
If there was no friction between the object and the plane, the
parallel component of the object’s weight would accelerate the
object down the plane. However, because there is friction
between the object and the plane, the force of friction (f =
F
N
)
opposes the parallel component of force. In other words, the vector for the force of friction would point
up
the
plane as the object slides
down
the plane.
Imagine that the object is being pulled up the plane by the
tension of a thread connected to a hanging mass. Would the
sliding friction (f
k
=
k
F
N
) oppose the parallel component of
the object’s weight, or would the vector for the sliding fric-
tion be in the same direction as the parallel component? Both
forces would point
down
the plane as the object is pulled
up
the plane. If the object is pulled at a constant speed, then the
net force on the object is zero. Would the tension in the
thread, T, equal the sum of the parallel component and the
sliding friction?
Prediction
How will the sum of the parallel component of the block’s weight (F
) plus the sliding friction (f
k
) compare to the
weight of the hanging mass?
Figure 8.2: The Inclined Plane
F
F
Object
F
Inclined
plane
F
F
F
Friction
Block
f
k
Direction
of motion.
Inclined
plane
T
Figure 8.3: Force Diagram
Содержание ME-9502
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Страница 4: ... Statics System iv 012 12876B ...
Страница 20: ...Statics System Exp 2 Adding Forces Resultants and Equilibriants 16 012 12876B ...
Страница 24: ...Statics System Exp 3 Resolving Forces Components 20 012 12876B ...
Страница 28: ...Statics System Exp 4 Torque Parallel Forces 24 012 12876B ...
Страница 32: ...Statics System Exp 5A Center of Mass 28 012 12876B ...
Страница 36: ...Statics System Exp 5B Equilibrium of Physical Bodies 32 012 12876B ...
Страница 44: ...Statics System Exp 7 The Inclined Plane 40 012 12876B ...
Страница 50: ...Statics System Static Friction on an Inclined Plane 46 012 12876B ...
Страница 60: ...Statics System Exp 10 Simple Harmonic Motion The Simple Pendulum 56 012 12876B ...
Страница 66: ...Statics System Exp 11A Simple Harmonic Motion Physical Pendulum 62 012 12876B ...
Страница 70: ...Statics System Exp 11B Minimum Period of a Physical Pendulum 66 012 12876B ...
Страница 76: ...Statics System Exp 11C Simple Harmonic Motion Beam on a Spring 72 012 12876B ...
Страница 84: ...Statics System Exp 13 Simple Machines The Inclined Plane 80 012 12876B ...
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