39
©
Dinel, s.r.o. PDU–4xx–W
b). I
in
= 2,5 mA and I
n
= -0,0938, because of the normalized In value is lower than 0, the
segment defined by X1 and X2 will be selected. X1(PL) = 0, Y1(PL) = -50, X2(PH) = 10,
Y2(PH) = -30 and I
p
= 0. For these values the displayed value W @ -69.
c). I
in
= 20,5 mA and I
n
= 1,0313., because of the normalized I
n
value is higher than 1, the
segment defined by X10 and X11 will be selected, and X10(PL) = 90, Y10(PL) = 900,
X11(PH) = 100, Y11(PH) = 820 and I
p
= 0,9 for these values the displayed value W @ 795.
𝐼𝐼
𝑜𝑜𝑜𝑜𝑜𝑜
=
𝑊𝑊 − "𝑂𝑂𝑂𝑂𝑂𝑂𝑂𝑂"
"OUtH"-"OUtL"
× 16 𝑚𝑚𝑚𝑚 + 4 𝑚𝑚𝑚𝑚 𝑃𝑃𝑃𝑃𝑃𝑃 𝑃𝑃𝑃𝑃𝑟𝑟𝑟𝑟𝑟𝑟ℎ 4 − 20 𝑚𝑚𝑚𝑚
𝐼𝐼
𝑜𝑜𝑜𝑜𝑜𝑜
=
𝑊𝑊 − "𝑂𝑂𝑂𝑂𝑂𝑂𝑂𝑂"
"OUtH"-"OUtL"
× 20 𝑚𝑚𝑚𝑚 𝑃𝑃𝑃𝑃𝑃𝑃 𝑃𝑃𝑃𝑃𝑟𝑟𝑟𝑟𝑟𝑟ℎ 0 − 20 𝑚𝑚𝑚𝑚
𝐼𝐼
𝑛𝑛
=
𝐼𝐼
𝑖𝑖𝑛𝑛𝑝𝑝.
− 4
16
𝑃𝑃𝑃𝑃𝑃𝑃 𝑃𝑃𝑃𝑃𝑟𝑟𝑟𝑟𝑟𝑟ℎ 4 − 20 𝑚𝑚𝑚𝑚
𝐼𝐼
𝑛𝑛
=
𝐼𝐼
𝑖𝑖𝑛𝑛𝑝𝑝.
20
𝑃𝑃𝑃𝑃𝑃𝑃 𝑃𝑃𝑃𝑃𝑟𝑟𝑟𝑟𝑟𝑟ℎ 0 − 20 𝑚𝑚𝑚𝑚
𝑊𝑊 = 𝐼𝐼
𝑛𝑛
× (
"Hi C"
− "
Lo C"
) + "
Lo C"
𝑊𝑊 = 𝐼𝐼
𝑛𝑛
2
× (
"Hi C"
− "
Lo C"
) + "
Lo C"
𝑊𝑊 = √𝐼𝐼
𝑛𝑛
× (
"Hi C"
− "
Lo C"
) + "
Lo C"
𝑊𝑊 = (𝐼𝐼
𝑛𝑛
− 𝐼𝐼
𝑝𝑝
) ×
[𝑌𝑌 (𝑃𝑃𝑃𝑃) − 𝑌𝑌 (𝑃𝑃𝑂𝑂)]
[𝑋𝑋 (𝑃𝑃𝑃𝑃) − 𝑋𝑋 (𝑃𝑃𝑂𝑂)] × 100 + 𝑌𝑌 (𝑃𝑃𝑂𝑂)
𝑊𝑊 = (𝐼𝐼
𝑛𝑛
− 𝐼𝐼
𝑝𝑝
) ×
[𝑌𝑌 (𝑃𝑃𝑃𝑃) − 𝑌𝑌 (𝑃𝑃𝑂𝑂)]
[𝑋𝑋 (𝑃𝑃𝑃𝑃) − 𝑋𝑋 (𝑃𝑃𝑂𝑂)] × 100 + 𝑌𝑌
(𝑃𝑃𝑂𝑂)
= (0,375 − 0,3) ×
[80 − 30]
[40 − 30] × 100 + 30 ≅ 67
a). I
in
=10 mA a I
n
= 0,375
The segment defined by X6 = “30.0.” and X7 = “40.0.” for this I
n
will be selected.
Accordingly to expressions given for user defined characteristic (see page 39) X6(PL) =
30, Y6(PL) = 30, X7(PH) = 40, Y7(PH) = 80 and I
p
= 0,3 , the displayed value :