NexSys
®
Modules
= 528
2046
= (2*1000) + (0*100) + (4*10) + (6*1)
= 2000 + 000 + 40 + 6
= 2046
However, since this is really only converting decimal back into decimal, it is of limited
usefulness. Retaining the above concepts and applying it to the other numbering
systems makes things much more clear. Looking at Base-2, digits are in very short
supply. Counting from zero, one has “0,” “1,” and then one must start again. Add a
placeholder, and again the result is “10.” However, now “10” represents two, not ten.
The “1” in “10” binary has a value of two times the place to its right, and the place
to it’s right has a one’s value.
Analyzing this example with the approach used above:
10 = (1*two) + (0*one) = two
It becomes readily apparent that “10” does not always represent “ten,” it is entirely
dependent on the base of the numbering system being used. Other binary values:
100011 b
= (1*32) + (0*16) + (0*8) + (0*4) + (1*2) + (1*1)
= 32 + 0 + 0 + 0 + 2 + 1
= 35
1000010000 b
= (1*512) + (0*256) + (0*128) + (0*64) + (0*32) + (1*16) + (0*8) + (0*4)
+ (0*2) + (0*1)
= 512 + 0 + 0 + 0 + 0 + 16 + 0 + 0 + 0 + 0
= 528
11111111110 b
= (1*1024) + (1*512) + (1*256) + (1*128) + (1*64) + (1*32) + (1*16) + (1*8)
+ (1*4) + (1*2) + (0*1)
= 1024 + 512 + 256 + 128 + 64 + 32 + 16 + 8 + 4 + 2 + 0
= 2046
Of course, a similar approach can be applied to hex. However, this time there are
more digits than in decimal. Now, counting to “9” is the same as in decimal, but it
is possible to continue on with “A,” “B,” “C,” “D,” “E,” and “F.” It is only once “F” is
exceeded that a new placeholder is required, and it will of course have a value
sixteen times that of the placeholder to its right. If we use our example of “10” again,
the “1” is worth sixteen, so the number represented in this case is sixteen.
Approaching “10” with the above method in hex:
10 = (1*sixteen) + (0*one) = sixteen
C
Kd
owner’s manual
CKd Series Owners Manual v1e
Page
21
Содержание CKd Series
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