SSI30 Wood Insert
8
63D4004
ClEARANCES
A
B
C
D
E
F
ST1065
SSI30 clearances
Sidewall
Mantel
Fascia or
Trim
ST1065
Figure 3 -
Clearances to Combustibles
Clearance to Combustibles
Minimum
A. To side wall
11" (279 mm)
B. To mantel (12" max.)
23" (584 mm)
C. To top trim (3/4" max.)
16" (406 mm)
D. To side trim (3/4" max.)
7" (178 mm)
Floor protection
E. In front of insert (1/2" min.)
18" (457 mm)
F. To side of insert
8" (203 mm)
12”
Max
ST1066
mantel clearance
Offset
Adapter
ST1066
Figure 4 -
Mantel Clearance
CAlCulATINg ACCEpTAblE AlTERNATE
FlOOR MATERIAlS
All floor protection must be non-combustible (i.e. metal,
brick, stone, mineral fiber, etc.). Any organic materials (i.e.
plastics, wood or paper products, etc.) are combustible and
must not be used. The floor protection specified includes
some form of thermal designation such as R-value (thermal
resistance) or k-factor (thermal conductivity).
PROCEDURE:
1. Convert specification to R-value:
•
R-value given. No conversion needed.
•
k-factor is given with a required thickness (T) in
inches: R = (1/k x T
•
k-factor is given with a required thickness (T) in
inches: R = (1/Kx12) x T
•
r-factor is given with a required thickness (T) in
inches: R = r x T
2. Determine the R-value of the proposed alternate floor
protector.
a. Use the formula in step (1) to convert values not
expressed as "R."
b. For multiple layers, add R-values of each layer to
dtetermine overal R-value.
3. If the overall R-value of the system is greater than the
R-value of the specified floor protector, the alternate
is acceptable.
EXAMplE:
The specified floor protector should be 3/4"
thick material with a k-factor of 0.84. The proposed alter-
nate is 4" brick with and R-factor of 0.2 over 1/8" mineral
board with a k-factor of 0.29.
Step A. Use formula above to convert specification to R-
value. R= (1/k) x T = (1/.84) x 0.75 = 0.893
Step B. Calculate R of proposed system.
4" brick of R = 0.2, therefore: R
brick
= 0.2 x 4 = 0.431
1/8" mineral board of k = 0.29, therefore: R
mineral board
= x
0.125 = 0.431
R
total
= R
brick
+ R
mineral board
= 0.8 + 0.431 = 1.231
Step C. Compare proposed system R
total
of 1.231 to
specified R of 0.893. Since proposed system R
total
is
greater than required, the system is acceptable.
FlOOR pROTECTION
Floor protection must be at least 3/4" minimum non-
combustible material with a “K” value of 0.84, extending
18" (457 mm) in front of and 8" (203 mm) to the side of
the fuel loading door (in the United States). In Canada, it
must extend 450 mm to the front and 200 mm to the side
of the unit.
r = =
(ft
2
)(hr)(°F)
(Btu)(in)
1
k
(Btu)(ft)
(ft
2
)(hr)(°F)
K =
k = = K x 12
(Btu)(in)
(ft
2
)(hr)(°F)
R = (ft
2
)(hr)(°F)
Btu
