No.IP8S-OM00009
15
■
Electrical Wiring
Table 8
Terminal no.
Description
Electric wire diameter
Remarks
1
4 to 20mA DC
input current
It corresponds to the 0.14~1.5mm
２
stranded wire and AWG26-14.
Minimum input current of 3.85mA
DC is required for operation.
2
3
Analog output
＊
2
Output range: 3.85 to 24mADC
4
5
Alarm output 1
＊
3,
＊
4
－
6
7
Alarm output 2
＊
3,
＊
4
8
HART
HART communication
－
－
2: Calculate the maximum load resistance compatible with analog output from the specifications table (Table
2) and following equation (Common for both non-explosion protected specification and intrinsic safety
type of explosion protected construction specification).
<Ex.: Analog output>
Power supply voltage of 24V DC,
Load resistance
＝
(24V DC
－
10V DC) / 24mA DC = 583
Ω
(Up to 0 to 583
Ω
)
3: Alarm output for non-explosion protected specification requires 10mADC or more to operate the main
circuit of the internal switch, and it should be 40mADC or less to protect the internal resistance circuit.
Therefore, use a power supply voltage and load resistance with a load current of 10 to 40mADC when the
output is on.
<Ex.: Alarm output 1>
Power supply voltage 24V DC and load resistance 1k
Ω
(+ internal resistance 350
Ω
),
Load current = 24V DC / (1k
Ω
+ 350
Ω
) = Approx. 18mA DC
4: Determination of load resistance of alarm output for intrinsic safety type of explosion protected
construction specification.
<Ex.: Alarm output 1>
Power supply voltage 24V DC,
Load current = 24V DC
– 5V DC / 3.15mA DC = 6080
Ω
(Up to 0 to 6.08k
Ω
)
Fig. 10
Input current
Power supply
voltage
Load
Load
Terminal No.
１
３
２
４
３
５
４
６
５
７
６
８
７
９
８
７
９
+
-
+
-
+
-
+
-
Load
Ａ
Power supply
voltage
Power supply
voltage
HART
communication
terminal
A
