Gas Correction Factor
Chapter Three: Overview
50
Example:
Calculate the GCF for a gas mixture of argon (gas 1) flowing at 150 sccm and nitrogen (gas 2)
flowing at 50 sccm, where:
Argon (Ar)
Nitrogen (N
2
)
a
1
=
150
=
0.75
a
2
=
50
=
0.25
200
200
s
1
=
1.030
s
2
=
1.000
d
1
=
1.782 g/l
d
2
=
1.250 g/l
cp
1
=
0.1244 cal/g ° C
cp
2
=
0.2485 cal/g ° C
then:
GCF
M
=
(0.3106) [(0.75)(1.030) + (0.25)(1.000)]
(0.75)(1.782)(0.1244) + (0.25)(1.250)(0.2485)
=
(0.3106) [(0.7725) + (0.25)]
(0.1663) + (0.0777)
=
(0.3106) (1.0225)
0.244
=
0.3176
0.244
GCF
M
= 1.302
Summary of Contents for 246C
Page 3: ...120715 P1 Rev A 2 98 MKS Type 246C Single Channel Power Supply Readout...
Page 10: ...List of Figures and Tables viii...
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