Installation Manual
39
ENGLISH
Refrigerant piping system
Calculation of amount of refrigerant
The calculation of the additional charge should take into account the length of pipe.
Additional charge (kg)
Product Charge(kg)
=
+
+
+
+
+
+
=
+
Total liquid pipe (m): Ø22.2mm
x 0.354(kg/m)
x 0.266(kg/m)
x 0.173(kg/m)
x 0.118(kg/m)
x 0.061(kg/m)
x 0.022(kg/m)
Total liquid pipe (m): Ø19.05mm
Total liquid pipe (m): Ø15.88mm
Total liquid pipe (m): Ø12.7mm
Total liquid pipe (m): Ø9.52mm
Total liquid pipe (m): Ø6.35mm
CF(kg)
(Correction Factor)
Total amount(kg)
If a negative result is obtained from
the calculation, no refrigerant needs
to be added.
A
A
B
B
CAUTION
B
B
B
B
B
A
B
C
X
b
a
c
d
3
4
5
2
1
e
Outside Unit
Indoor Unit
A : ø9.52, 40m
B : ø9.52, 20m
C : ø9.52, 20m
Ex
10HP
Additional Charge = A x 0.061 + B x 0.061 + C x 0.061
+ (a+b+c+d+e) x 0.022 + CF
= 40 x 0.061 + 20 x 0.061 + 20 x 0.061
+ (10 x 5) x 0.022 + (0) (CF)
=
5.98(kg)
a : ø6.35, 10m
b : ø6.35, 10m
c : ø6.35, 10m
d : ø6.35, 10m
e : ø6.35, 10m
u
Special condition
In case of the No. of CST TQ/RAC SE/ARTCOOL SF models are over than 50% of the connected
indoor units when the total No. of connected indoor units are over than 50% of the max. connectable
indoor units.
n
Additional refrigerant charging amount (kg) :
Ⓒ
= (A x
α
+ B x ß) - (AVG x ß)
• A = Total No. of TQ,SE and SF Indoor units,
α
= 0.5
• B = Total No. of except TQ,SE and SF Indoor units,
ß = 0.3
• AVG = 50% of Max. No. of connectable Indoor units.
Example)
1) Installation Information
- Outside unit : 6HP
- Total indoor units : 6 units (TQ 3 units, SE 2 units, BH 1 unit)
2) Information from PDB
- Max. No. of connectable indoor units : 10 units
- Calculated additional refrigerant amount = 2 kg :
Ⓑ
3) Indoor refrigerant charging amount
= (5 units x 0.5+1 unit x 0.3) - (5 units x 0.3) = 1.3 kg :
Ⓒ
▶
Revised the total additional charging amount =
Ⓑ + Ⓒ
= 2 kg +1.3 kg
= 3.3 kg
+
=
Total amount(kg)
A
B
+
C
Summary of Contents for MULTI V WATER II ARWN Series
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