LIFTING LOADS
111
3
rd
Example
Given a 180-unit load to be lifted to the height of 10 m, find point
Z
(inside the 200-unit area) given by the inclina-
tion of the boom equal to 54° and the extension included between
F
and
G
.
The 10 m height can be reached more quickly and with more precision if operating with well defined boom exten-
sions and inclinations; in fact, this height can be reached even with boom extension corresponding to letters
E
and
D
, provided that the inclination (respectively 63° and 73.3°) corresponding to points
Z1
and
Z2
be varied.
NOTE
• The choice of the possible extension to be used depends exclusively on the position of the front part of
the machine with respect to fixed obstacles (walls, gutters, etc.) and on the load deposit distance with
respect to the point that can be reached by the machine.
RKA02310
RADIUS (m)
0.5 m
12
13
14
0
1
2
3
4
5
6
7
8
9
10
11
-1
15 m
11 m
9
8
7
6
5
4
3
2
1
0
-1
-2
10
150
G
F
E
D
C
B
A
100100100
150150150
HEIGHT
(m)
ZZZ
350
350
350
400
400
400
454545
Z1
Z1
Z1
Z2
Z2
Z2
300
250250250
200200200
Summary of Contents for 395F6001
Page 2: ......
Page 21: ...SAFETY DEVICES AND ACCIDENT PREVENTION MEASURES 19 ...
Page 23: ...SAFETY NOISE AND VIBRATION PLATES 21 395 93 11391 RKAA0400 ...
Page 24: ...SAFETY NOISE AND VIBRATION PLATES 22 RKAA0740 RKAA0720 ...
Page 25: ...SAFETY NOISE AND VIBRATION PLATES 23 RKAA0710 ...
Page 66: ...PAGE INTENTIONALLY LEFT BLANK ...
Page 67: ...DESCRIPTION AND OPERATION OF THE MACHINE 65 ...
Page 168: ...PAGE INTENTIONALLY LEFT BLANK ...
Page 169: ...MAINTENANCE 167 ...
Page 239: ...TECHNICAL DATA 237 ...
Page 253: ......
Page 254: ... 2004 KOMATSU UTILITY EUROPE S p A All Rights Reserved Printed in Europe ...