4.2 Horizontal protection of hazardous areas
FIESSLER
E L E K T R O N I K
11
4 Installation
- Safe distances
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Calculation examples for the safe distance with
horizontal protection of hazardous areas using
ULVT light barrier:
Example:
ULVT1200/156 light barrier
Response time t1 of light barrier: 18 ms
Run-on time t2 of machine: 50 ms
H = 200 mm
The safe distance is:
S =
(1600 mm / s x (0.050 s + 0.018)) +
(1200 mm - 0.4 x 200 mm)
S = 1229 mm
With the ULVT 1200/156, the protective field
depth is 1200 mm.
A distance a between protective field and
machine of 53 mm provides a safe distance
S = 1253 mm
Formula for calculating the safe
distance with horizontal protection of
hazardous areas using a light barrier:
Here:
K = 1600 mm/s
C = 1200mm-0.4H, but smaller than 850
mm, whereby H is the height in mm
of the protective field above the
reference level, e.g. floor.
With a height of the protective field above
the floor of > 300 mm, a risk of crawling
under exists. This must be considered in
risk assessment.
The following condition thus applies for H
≥
300 mm:
1200 - 0.4 x H > 850 mm
The distance a of the end of the
protective field (last beam to front
edge of hazardous area) must be
no more than:
Example:
Height 200 mm
a = 200 / 15 + 40 mm
a = 53 mm
S = (1600 mm / s x T) + (1200 mm - 0,4 H)
a = H / 15 + 40 mm
S =
Safe distance
Start of protective field (first beam) to
front edge of hazardous area
H
Front edge of hazardous area
H = Height of protective field to reference level
S = (K x T) + C
a =
Distance from last beam of protective
field to front edge of hazardous area
S
a
BA - ULVT