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Unit installation
Installer and user reference guide
48
FXSN50~112A2VEB
CO₂ Conveni-Pack: indoor unit
4P602817-1A – 2020.05
a
Outdoor unit
b
Stop valve on the outdoor unit
c1
Liquid piping between outdoor unit and the shut off valve
c2
Liquid piping between indoor unit and the shut off valve
d1
Gas piping between outdoor unit and the shut off valve
d2
Gas piping between indoor unit and the shut off valve
e
Bypassing piping
f
Safety shut off valve
g
Pressure relief valve
h
Indoor unit
To determine the minimum number of appropriate measures
For occupancies other than on the lowest underground floor of the building
If the total refrigerant charge (kg)
divided by the room volume
(a)
(m
3
) is…
…the number of appropriate measures
must be at least…
<QLMV
0
>QLMV and <QLAV
1
>QLAV
2
(a)
For occupied spaces with a floor area exceeding 250 m
2
, use 250 m
2
as the floor area for
determination of the room volume (
Example:
even if the room area is 300 m
2
and the
room height is 2.5 m, calculate the room volume as 250 m
2
× 2.5 m = 625 m
3
)
Example:
Total refrigerant charge in the system is 45 kg and room volume is
300 m
3
. 45/300 = 0.15, which is >QLMV(0.074) and <QLAV(0.18), therefore install
at least 1 appropriate measure in the room.
A (kg)
B (m³)
0
0
100 150
50
200 250
300
350
450
550
400
500
600 650 700 750 800 850 900 950 1000
5
10
15
20
25
30
35
40
45
50
55
60
65
70
c
b
a
QLMV
QLAV
15‒2 Example graph for calculation
A
Refrigerant charge
B
Room volume
a
2 appropriate measures required
b
1 appropriate measure required
c
No measure required
For occupancies on the lowest underground floor of the building
If the total refrigerant charge (kg)
divided by the room volume
(a)
(m
3
) is…
…the number of appropriate measures
must be at least…
<RCL
0
>RCL and ≤QLMV
1
>QLMV and <QLAV
2
>QLAV
Value CANNOT be exceeded!
(a)
For occupied spaces with a floor area exceeding 250 m
2
, use 250 m
2
as the floor area for
determination of the room volume (
Example:
even if the room area is 300 m
2
and the
room height is 2.5 m, calculate the room volume as 250 m
2
× 2.5 m = 625 m
3
)