14
/
17
from the zero to proximity switch is greater than 100 000 steps, less than 100010 steps). Design
analysis: the variable displacement of this movement does not know its precise value, but only
know it's a general range (belong to a unknown variable). We use a method for interrupting
operation to solve this problem. We connect the limit switch to the A operating port, Due the
interrupt operation,the motor will slow down to stop, If run to the limit switch as a high-speed
directly,will produce overshoot, In order to avoid the overshoot, we use this method that the first
run as a high-speed ,then run as a low-speed (low-speed is below the starting frequency).
Parameter List:
(Enter the parameter setting mode to modify) Setting A Operator address nA = 04,
other parameters are ignored.
Program Listing :
( enter the program edit state)
00 SPEED 39000 ; assign the speed as 39KHz
01 G-LEN 0099000 ; First, high-speed close to, but can
’
t hit the limit switch
02 SPEED 00400 ; low-speed frequency must below the starting frequency
03 G-LEN 07999999 ; The amount of displacement is set to the maximum, to reach the limit
switch
04 SPEED 39000 ; A Operator, assign the return to zero speed as 39KHz
05 GO-AB -A ; In the opposite direction, running the same amount of displacement,back to zero
06 END; the program ends!
Ⅻ
. directive search form
N
O.
Directive
Name
Example
Instructions, data range, unit
Directive
full name
Directive
abbreviati
on
1
pause
directive
00 PAUSE
Program pauses, waiting for the start signal
PAUSE
PAU
2
displacemen
t directive
01
G-LEN
-1234567
According to the latest SPEED assignment speed, reverse
mobile 1234567 step; pulses number
G-LEN
G-L
3
Speed
assignment
directive
02
SPEED
12345
Run this directive following assignment speed; 12345Hz
1-39999, pulses / sec (Hz)
SPEED
SPD
4
Delay
directive
03
DELAY
1234567
Delay time: 1234567 ms 1-7999999, ms
DELAY
OLY
5
Uncondition
al
jump
directive
04 JUMP
12
Unconditional jump to the line XII program runs
00-99, line number
JUMP
JMP
6
Cycle
directive
05 LOOP
03 12345
Jump from the current line to the (05) to 03 lines
for 12,345 cycles 1-99999 (0 defined as infinite),
Times (only forward loop)
LOOP
LOP
7
Move to
a position
06
GOTO
-1234567
Control the motor running to coordinate the
position of -7999999- + is -1,234,567 7,999,999,
the number of pulses (0 equivalent return to zero)
GOTO
GOT
8
Output
directive
07 OUT
03 01 N 0
Switch output is: 0UT = (K 0UT2 = 1,0UT3
unchanged internal buzzer a short sound (a =
long beep, N = no sound)
OUT
OUT
