Rexnord 1874, Инструкция по эксплуатации

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Conveyor
Section
1
2
(CASE B)
EXAMPLE 1 :
CONVENTIONAL CONVEYOR
PARAMETERS:
Chain Weight = 1 0 Lb /Ft. (1701 TAB)
Product Weight = 5
= 0.25
fm =
25 Ft. Slippage from Head Sprocket
20 1.0 0.25 5.0 5.8
30 1.0 0.25 7.5
Speed = 120 FPM
= 5 Per Hour
PLF = 1.5
SECTION #4
3
4
30 6.0 0.25 45 .0
5 5.0 0.18 4.5 62 .8 1.15 72 .2
20 6.0 0.25 30 .0 102 .2
20 5.0 0.18 18.0
6
TA = CT x PLF
= 180.3 Lbs.
Where
TA = Tension. Adjusted
CT = Chain Tension
RETURN
SUPPORT
IDLER
SECTION #2
SECTION #1
20"
SECTION #3
30"
IDLER
WHEEL
DRIVE
SPROCKET
CORNER
DISCS
Lb /Ft.
fw
0.18
Stop-Start
5.0 + 0 1.15
13.3
"L"
Section
Length
(Ft.)
"W"
Chain
Weight
(Lbs./Ft.)
"fw"
Coefficient
of Friction
Chain
Tension
(Lbs.)
1 x 2 x 3
Chain
Tension
into The
Turn
(Lbs.)
4 + Prev 7
Turn Factor
(TF) 1.15
TF Used
For The Section
(Lbs.)
5 x 6
No TF Used
For The Section
(Lbs.)
4 + Prev 7
Chain Tension
Slip-4
Slip-3
1 2 3 4 5 6 7
Tr = Tension in Return Section
Tc + Ts = Tension in Carry S Slippage
120.2 (CT)
58.3
1 2 3 4 5 6 7
Conveyor
Section
"L"
Section
Length
(Ft.)
"W + M"
Chain +
Product
Weight
(Lbs./Ft.)*
"fw"
Coefficient
of Friction**
Chain
Tension
(Lbs.)
1 x 2 x 3
Chain
Tension
into The
Turn
(Lbs.)
4 + Prev 7
Turn Factor
(TF) 1.15
TF Used
For The Section
(Lbs.)
5 x 6
No TF Used
For The Section
(Lbs.)
4 + Prev 7
Chain Tension
* For "Slip", only use "M"
** For "Slip" use "fm"
120.5 x 1.5
CALCULATION
OF CHAIN
TENSION FOR
MULTIFLEX
CHAINS
Re
x
®
Multifle
x Chains
Rex ® Engineering Manual MF-10