I
I
I
I
I
DRIVE
SUPPORT
IDLER
ROLLERS
CATENARY
ROLLER
BI-DIRECTIONAL CONVEYORS
Figure 29 End Drive Conveyor
The following examples show two methods
of driving a bi-directional conveyor with one drive.
Span
Inches
(mm)
Sag Inches (mm)
IDLER ROLLER
SPAN
SAG
10 (250)
20 (500)
30 (750)
40 (1000)
50 (1250)
60 (1500)
70 (1750)
80 (2000)
90 (2250)
100 (2500)
110 (2750)
120 (3000)
0.6 (1,77)
1.6 4,81)
3.4 (10,20)
5.8 (17,40)
8.9 (26,70)
12.8 (38,30)
17.3 (52,00)
22.5 (67,70)
28.4 (85,30)
35.0 (105,00)
42.3 (127,00)
50.3 (151,00)
0.6 (1,77)
1.4 (4,22)
2.7 (10,20)
4.5 (13,40)
6.8 (20,40)
9.7 (29,00)
13.1 (39,20)
17.0 (50,80)
21.4 (64,10)
26.4 (79,10)
31.8 (95,20)
37.8 (113,00)
0.6 (1,77)
1.3 (3,92)
2.3 (6,90)
3.8 (11,40)
5.6 (16,80)
7.9 (23,60)
10.6 (31,70)
13.8 (41,30)
17.3 (51,80)
21.3 (63,80)
25.6 (76,60)
30.4 (91,20)
0.7 (2,06)
1.2 3,63)
2.1 (6,30)
3.3 (9,90)
4.8 (14,30)
6.8 (20,40)
9.0 (27,00)
11.6 (34,70)
14.6 (43,80)
17.9 (53,60)
21.5 (64,40)
25.5 (76,30)
0.7 (2,06)
1.2 (3,63)
1.9 (5,70)
3.0 (9,00)
4.3 (12,90)
5.9 (17,70)
7.9 (23,60)
10.1 (30,20)
12.6 (37,80)
15.5 (46,40)
18.6 (55,70)
22.0 (65,80)
0.8 (2,35)
1.2 (3,63)
1.8 (5,40)
2.8 (8,30)
3.9 (11,70)
5.4 (16,20)
7.0 (21,00)
9.0 (27,00)
11.2 (33,60)
13.7 (41,00)
16.4 (49,10)
19.4 (58,10)
0.9 (2,65)
1.2 (3,63)
1.8 (5,40)
2.6 (7,70)
3.6 (10,80)
4.9 (14,70)
6.4 (19,10)
8.2 (24,50)
10.1 (30,20)
12.3 (36,80)
14.8 (44,30)
17.4 (52,00)
0.9 (2,65)
1.3 (3,92)
1.8 (5,40)
2.5 (7,50)
3.4 (10,20)
4.6 (13,70)
5.9 (17,70)
7.5 (22,50)
9.3 (27,90)
11.3 (33,80)
13.4 (40,10)
15.8 (47,40)
1.1 (3,34)
1.3 (3,92)
1.8 (5,40)
2.4 (7,20)
3.2 (9,60)
4.1 (12,30)
5.3 (15,90)
6.6 (19,70)
8.0 (23,90)
9.7 (29,00)
11.5 (34,40)
13.5 (40,40)
3.0 (75)
4.0 (100)
5.0 (125)
6.0 (150)
7.0 (175)
8.0 (200)
9.0 (225)
10.0 (250)
12.0 (300)
TABLE 8 - (T) CATENARY TENSION - POUNDS (NEWTONS) FOR CHAIN WEIGHING
ONE POUND PER FOOT
2
(OR ONE KILOGRAM PER METER
2
)
The end drive method is recommended for light duty service
(10'-20' centers) on conveyors where the chain tension on
the carry side can be balanced by the catenary tension. Use
Table 8 to calculate catenary tension "T". This tension must
be equal to, within 5%, the carry side chain tension for proper
operation.
In addition, when calculating chain tension per foot of width,
use twice the calculated carry side chain tension to
determine chain load carrying capability. This is adjusted
chain tension. This is to allow for chain tension in the
catenary section, that is equal to carry side chain tension.
For determining horsepower, use standard tension, (CT).
Example:
Conveyor length = 12 ft.; top load - 11 lb./ft.
2
,
chain = LF5997 @ 3.4 lb./ft.
2
; calculated chain
tension = 43 lb./ft. of width. Therefore, catenary
tension (T), should equal 43 lbs. "T", from Table
8, is multiplied by the chain weight to determine
span length and depth required. The minimum "T"
from Table 8 required to get 43 lb. tension is 12.8,
(12.8 x 3.4 = 43.5).
This corresponds to a 60" span and a 3" sag. Other
combinations are possible.
For applications beyond the capacity of the end
drive method, use the bottom drive arrangement.
SELECTION
PROCEDURE
cont.
Conveyor
Design and
Construction
cont.
Re
x
®
MatT
op
®
Chains
Rex
®
Engineering Manual MT-14
Содержание 1874
Страница 1: ... Rex Engineering Manual ...
Страница 2: ...Rex TableTop Engineering Manual ...
Страница 13: ...Rex MatTop Engineering Manual ...
Страница 35: ...Rex Multiflex Engineering Manual ...