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FX 146
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34
316 IF NK < 16 THEN NL = NK
320 IF NL => 8 THEN MM = 1
325 IF NL > 8 THEN NM = NL - 8
326 IF NL < 8 THEN NM = NL
330 IF NM => 4 THEN NN = 1
335 IF NM > 4 THEN NX = NM - 4
336 IF NM < 4 THEN NX = NM
340 IF NX > 2 THEN OO = 1
345 IF NN = 2 THEN OO = 1
346 IF NX = 3 THEN PP = 1
347 IF NX = 1 THEN PP = 1
400 PRINT “32768 - “; AA
405 PRINT “16384 - ”; BB
410 PRINT “ 8192 - “; CC
415 PRINT “ 4096 - “; DD
420 PRINT “ 2048 - “; EE
425 PRINT “ 1024 - “; FF
430 PRINT “ 512 - “; GG
435 PRINT “ 256 - “; HH
440 PRINT “ 128 - “; II
445 PRINT “ 64 - “; JJ
450 PRINT “ 32 - “; KK
455 PRINT “ 16 - “; LL
460 PRINT “ 8 - “; MM
465 PRINT “ 4 - “; NN
470 PRINT “ 2 - “; OO
475 PRINT “ 1 - “; PP
480 PRINT “The Binary Equivalent of N can also look like this: “
481 PRINT “_______________________________________ “
482 PRINT USING “##”; AA, BB, CC, DD, EE, FF, GG, HH, II, JJ, KK, LL, MM, NN, OO, PP
485 PRINT
505 CLEAR.
510 GOTO 50
520 END
Here’s an example of the screen display for the program as written, showing
the results for an entry of “
146865”
and ready for the next frequency to be
entered as 6 digits:
For example: 146.52 MHz. = 146520. Enter here >>> ? 146865
The FX146 or FX220 N number for binary conversion is: 29373
32768 - 0
16384 - 1
8192 - 1
4096 - 1
2048 - 0
1024 - 0
512 - 1
256 - 0
128 - 1
64 - 0
32 - 1
16 - 1
8 - 1
4 - 1
2 - 0
FX-146
•
113
Even though there are 16 matrix positions to program, there are some
shortcuts to make your job easier for normal ham band operation. Let's look
at the upper and lower band edges for the 2 Meter band:
Notice that the values of the highest 6 positions are the same throughout the
band. We still must program in those six positions but we only need to
calculate for the remaining 10 (512 through 1).
Let's look again at the programming of 146.52 MHz Simplex, where N =
29,304. First, we see that the 16K, 8K and 4K positions are always
programmed with a diode and that the 32K, 2K and 1K positions never have
a diode installed. Let's put that fact to practical use:
1.
We will always install diodes in the 16K, 8K and 4K positions.
This gives us an 'initial' N value of: 16,384 + 8,192 + 4,096 =
28,672
2.
This number can be used to START programming ANY
frequency within the Amateur 2 Meter Band. We need only add
additional diodes in the 512 through 1 positions for the various
channels within the band.
3.
We determine these additional diodes by the same "Descending
Attempted Subtraction," that we used above for studying the
programming of 146.52 MHz Simplex, a process which you can
do in your head, with scratchpaper, or on the FX146
Programming Worksheet.
Let's do an example:
1.
We're already familiar with the right answer for 146.52 simplex,
let's use it again. N = 146520 ÷ 5 = 29,304
2.
Since we have already installed diodes in the 16K, 8K and 4K
positions, our 'initial' N is 28,672. The N we need is 29,304.
3.
We now figure the difference between the N needed and the
'initial' N: 29,304 - 28,672 = 632
4.
Now, using the "Attempted Subtraction" technique, find the
remaining binary value to be programmed.